A, B, C, D, E and F live on six different floors of the same building. The lowermost floor in the building is numbered 1, the floor above it, number 2 and so on till the topmost floor is numbered 6. The product of floors on which D and F live is 10. C lives immediately above E. The sum of floors on which B and D live is 11. How many people live between A and E?

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  1. 4
  2. 1
  3. 2
  4. 3

Answer (Detailed Solution Below)

Option 2 : 1
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Detailed Solution

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Given: A, B, C, D, E and F live on six different floors of the same building, numbered 1 to 6 from bottom to top.

Let's use the given conditions to deduce the floor arrangements:

1. The product of floors on which D and F live is 10.

Possible pairs for (D, F) or (F, D) that multiply to 10 are (2, 5) or (5, 2).

  Case I Case II
Floor No. Person Person
6    
5 D F
4    
3    
2 F D
1    

 

The sum of the floors on which B and D live is 11.

  • Given D can be on floor 2 or 5:
  • If D lives on floor 2, then B + 2 = 11 → B = 9 (case II is not possible as max floor is 6).
  • If D lives on floor 5, then B + 5 = 11 → B = 6.

We can definitely say that D lives on floor 5 and B lives on floor 6.

  Case I
Floor No. Person
6 B
5 D
4  
3  
2 F
1  

2. C lives immediately above E.

This means C and E are on consecutive floors, with C on the higher floor.

Floor No. Person
6 B
5 D
4 C
3 E
2 F
1  


The only person left is A, and the only floor left is 1. So, A lives on floor 1.

Final arrangement:

Floor No. Person
6 B
5 D
4 C
3 E
2 F
1 A
 

Thus, 1 person lives between A and E.

Hence, the correct answer is "Option 2".

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