Qualitative and Quantitative Analysis of Organic Compounds MCQ Quiz in தமிழ் - Objective Question with Answer for Qualitative and Quantitative Analysis of Organic Compounds - இலவச PDF ஐப் பதிவிறக்கவும்
Last updated on Mar 27, 2025
Latest Qualitative and Quantitative Analysis of Organic Compounds MCQ Objective Questions
Top Qualitative and Quantitative Analysis of Organic Compounds MCQ Objective Questions
Qualitative and Quantitative Analysis of Organic Compounds Question 1:
What type of information is collected using scanning electron microscopy?
Answer (Detailed Solution Below)
Qualitative and Quantitative Analysis of Organic Compounds Question 1 Detailed Solution
CONCEPT:
Scanning Electron Microscopy (SEM)
- Scanning electron microscopy (SEM) is a type of electron microscope that produces images of a sample by scanning it with a focused beam of electrons.
- The electrons interact with atoms in the sample, producing various signals that can be detected and contain information about the surface topography and composition of the sample.
EXPLANATION:
- Scanning Electron Microscopy (SEM) is primarily used to obtain high-resolution images of the surface of materials.
- It provides detailed information about the morphology and surface structure of the sample.
- The electron beam scans the sample surface and the interactions between the electrons and the atoms generate signals that form an image.
- Other options such as crystal structure, binding nature, and particle size are typically not determined directly by SEM:
- Crystal structure is usually analyzed using techniques like X-ray diffraction (XRD).
- Binding nature can be studied using spectroscopic methods.
- Particle size can be analyzed using techniques like dynamic light scattering (DLS) or transmission electron microscopy (TEM).
Therefore, the correct answer is option 1: Structure of material surface.
Qualitative and Quantitative Analysis of Organic Compounds Question 2:
In Kjeldahl’s method of estimation of nitrogen, K2SO4 acts as:
Answer (Detailed Solution Below)
Qualitative and Quantitative Analysis of Organic Compounds Question 2 Detailed Solution
Concept:
Kjeldahl’s method is a widely used technique for estimating the nitrogen content in organic compounds. The procedure involves the digestion of the sample with concentrated sulfuric acid (H2SO4), where the organic nitrogen is converted to ammonium sulfate ((NH4)2SO4).
Explanation:
Various chemicals are added during the digestion process for specific purposes. Potassium sulfate (K2SO4) plays a particular role in this method:
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The primary function of K2SO4 is to raise the boiling point of the digestion mixture. This allows the digestion temperature to be increased, leading to the efficient and complete breakdown of the organic material.
Conclusion:
In Kjeldahl’s method of estimation of nitrogen, K2SO4 acts as: Boiling point elevator
Qualitative and Quantitative Analysis of Organic Compounds Question 3:
Distillation is used to separate liquids which differ in the boiling point by atleast _______°C
Answer (Detailed Solution Below) 25
Qualitative and Quantitative Analysis of Organic Compounds Question 3 Detailed Solution
Concept:
Distillation:
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It involves heating a liquid to create vapor and then cooling the vapor to create a liquid.
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Distillation separates components based on differences in their boiling points.
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It is commonly used in the purification of liquids and the separation of liquid mixtures.
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There are different types of distillation, including simple distillation, fractional distillation, and vacuum distillation, each suited for specific purposes.
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For distillation to effectively separate two liquids, they must differ in boiling points by at least 25°C.
Explanation:
Distillation leverages the boiling point difference between components in a mixture:
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When a mixture is heated, the component with the lower boiling point vaporizes first.
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The vapor is collected and cooled in a condenser to get a purified liquid (distillate).
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If the boiling points of the components are close (<25°C), fractional distillation with a longer fractionating column is used to achieve better separation.
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Vacuum distillation is employed for substances with very high boiling points to lower the boiling temperatures by reducing the ambient pressure.
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Efficient separation relies on maintaining accurate temperature control and steady heating rates.
Conclusion:
Distillation is effective for separating liquids which differ in the boiling point by at least 25°C.
Qualitative and Quantitative Analysis of Organic Compounds Question 4:
An inorganic salt is heated with ethyl alcohol and conc. H2SO4; vapours evolved produces green-edged flame on ignition; it indicates the presence of :
Answer (Detailed Solution Below)
Qualitative and Quantitative Analysis of Organic Compounds Question 4 Detailed Solution
Concept
When an inorganic salt is heated with ethyl alcohol and concentrated sulfuric acid (H2SO4), the resulting vapors may produce a characteristic colored flame upon ignition. Some key points about this reaction are:
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Concentrated H2SO4 acts as a dehydrating agent and facilitates the reaction by breaking down the salt and releasing volatile compounds.
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Ethyl alcohol (ethanol) is used as a medium, which can produce volatile esters and other compounds depending on the anion present in the salt.
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The color of the flame is a qualitative test, useful for identifying specific anions due to their distinct emission spectra when excited by heat.
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A green-edged flame is a specific indicator of the presence of borate ions (BO33-), which form volatile boron compounds that burn with a green edge.
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This flame test is a quick and effective way to identify certain anions in the laboratory without needing sophisticated equipment.
Explanation:
The characteristic flame colors associated with each of the given anions are:
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F- (Fluoride): Fluoride does not produce a characteristic flame color.
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C2O42- (Oxalate): Oxalate ion does not typically produce a colored flame.
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BO33- (Borate): Borate produces a green-edged flame when heated with ethyl alcohol and concentrated sulfuric acid due to the formation of volatile boron compounds.
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ClO3- (Chlorate): Chlorate ion can produce a violet or purple flame but not green-edged.
Conclusion:
The presence of a green-edged flame upon heating an inorganic salt with ethyl alcohol and concentrated H2SO4 indicates the presence of: BO33-
Qualitative and Quantitative Analysis of Organic Compounds Question 5:
A solution of Na2C2O4, when added to a solution containing Ba2+, Sr2+ and Ca2+ ions, will precipitate
Answer (Detailed Solution Below)
Qualitative and Quantitative Analysis of Organic Compounds Question 5 Detailed Solution
Concept:
When a solution of Na2C2O4 (sodium oxalate) is added to a solution containing various metal ions, it can result in the formation of insoluble oxalates. Important aspects to consider:
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Sodium oxalate can react with metal cations such as Ba2+, Sr2+, and Ca2+ to form insoluble oxalates.
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The solubility product (Ksp) values of the metal oxalates determine the extent to which each cation will precipitate.
Explanation:
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Ba2+: Barium oxalate (BaC2O4) has a very low solubility product, so Ba2+ ions will precipitate readily.
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\(\mathrm{Ba}\left(\mathrm{CH}_{3} \mathrm{COO}\right)_{2}+\mathrm{Na}_{2} \mathrm{C}_{2} \mathrm{O}_{4} \longrightarrow \underset{\text { white ppt. }}{\mathrm{BaC}_{2} \mathrm{O}_{4}}+2 \mathrm{CH}_{3} \mathrm{COONa}\)
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Sr2+: Strontium oxalate (SrC2O4) is also quite insoluble and will precipitate out of solution.
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\(\mathrm{Sn}\left(\mathrm{CH}_{3} \mathrm{COO}\right)_{2}+\mathrm{Na}_{2} \mathrm{C}_{2} \mathrm{O}_{4} \longrightarrow \underset{\text { white ppt. }}{\mathrm{SrC}_{2} \mathrm{O}_{4}}+2 \mathrm{CH}_{3} \mathrm{COONa}\)
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Ca2+: Calcium oxalate (CaC2O4) is similarly insoluble and will form a precipitate.
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\(\mathrm{Ca}\left(\mathrm{CH}_{3} \mathrm{COO}\right)_{2}+\mathrm{Na}_{2} \mathrm{C}_{2} \mathrm{O}_{4} \longrightarrow \underset{\text { white ppt. }}{\mathrm{CaC}_{2} \mathrm{O}_{4}}+2 \mathrm{CH}_{3} \mathrm{COONa}\)
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Thus, the addition of Na2C2O4 to a solution containing Ba2+, Sr2+, and Ca2+ ions will result in the formation of their respective oxalates, all of which are insoluble and will precipitate out of the solution.
Conclusion:
A solution of Na2C2O4, when added to a solution containing Ba2+, Sr2+ and Ca2+ ions, will precipitate are: Ba2+, Sr2+, and Ca2+ ions
Qualitative and Quantitative Analysis of Organic Compounds Question 6:
A reagent which gives brilliant red precipitate with Nickel ions in basic medium is
Answer (Detailed Solution Below)
Qualitative and Quantitative Analysis of Organic Compounds Question 6 Detailed Solution
CONCEPT:
Qualitative Analysis of Nickel Ions
- In qualitative inorganic analysis, specific reagents are used to identify the presence of certain metal ions based on the formation of characteristic precipitates.
- Nickel(II) ions (Ni2+) can be detected using dimethyl glyoxime (dmg), which forms a distinctive red precipitate with Ni2+ in a basic medium.
EXPLANATION:
- When dimethyl glyoxime is added to a solution containing Ni2+ ions in a basic medium, a chelation reaction occurs, forming a bright red precipitate.
- The reaction can be represented as follows:
Ni2+ + 2dmg- → Ni(dmg)2
- Here, Ni2+ is the nickel ion.
- dmg- is the dimethyl glyoxime anion.
- Ni(dmg)2 is the red chelate complex formed.
- This reaction is highly specific and is used as a qualitative test for the presence of nickel ions because of the distinct color change to a brilliant red precipitate.
Therefore, the reagent which gives a brilliant red precipitate with Nickel ions in a basic medium is dimethyl glyoxime (option 4).
Qualitative and Quantitative Analysis of Organic Compounds Question 7:
Match List I with List II :
List I (Precipitating reagent and conditions) |
List II (Cation) |
||
A. |
NH4Cl + NH4OH |
I. |
Mn2+ |
B. |
NH4OH + Na2CO3 |
II. |
Pb2+ |
C. |
NH4OH + NH4Cl + H2S gas |
III. |
Al3+ |
D. |
dilute HCl |
IV. |
Sr2+ |
Choose the correct answer from the options given below :
Answer (Detailed Solution Below)
Qualitative and Quantitative Analysis of Organic Compounds Question 7 Detailed Solution
CONCEPT:
Identifying Cations Using Precipitating Reagents
- NH4Cl + NH4OH: This combination is used to precipitate cations like Al3+.
- NH4OH + Na2CO3: Used to precipitate alkaline earth metals such as Sr2+.
- NH4OH + NH4Cl + H2S gas: This combination is used to precipitate metal sulfides such as Pb2+.
- dilute HCl: Used to precipitate cations such as Mn2+.
Explanation:-
List I contains reagents and conditions for precipitation.
List II contains cations that can be precipitated by the reagents and conditions in List I.
- A. NH4Cl + NH4OH -- III. Al3+
- B. NH4OH + Na2CO3 -- IV. Sr2+
- C. NH4OH + NH4Cl + H2S gas -- II. Pb2+
- D. dilute HCl -- I. Mn2+
The correct answer is A-III, B-IV, C-II, D-I
Qualitative and Quantitative Analysis of Organic Compounds Question 8:
Which of the following statements are correct ?
A. Glycerol is purified by vacuum distillation because it decomposes at its normal boiling point.
B. Aniline can be purified by steam distillation as aniline is miscible in water.
C. Ethanol can be separated from ethanol water mixture by azeotropic distillation because it forms azeotrope.
D. An organic compound is pure, if mixed M.P. is remained same.
Choose the most appropriate answer from the options given below :
Answer (Detailed Solution Below)
Qualitative and Quantitative Analysis of Organic Compounds Question 8 Detailed Solution
CONCEPT:
Purification Methods for Organic Compounds
- Vacuum Distillation:
- Used for compounds that decompose at their normal boiling point. Lowering the pressure allows the compound to boil at a lower temperature, avoiding decomposition.
- Steam Distillation:
- Used for compounds that are immiscible with water and have a sufficiently high vapor pressure at the boiling point of water.
- Azeotropic Distillation:
- Used to separate mixtures that form an azeotrope, which is a mixture with a constant boiling point that cannot be separated by simple distillation.
- Mixed Melting Point:
- Used to check the purity of an organic compound. A pure compound will have the same melting point when mixed with a small amount of the same compound.
Explanation:-
- A. Correct. Glycerol decomposes at its normal boiling point, so it is purified by vacuum distillation.
- B. Incorrect. Aniline is actually purified by steam distillation because it is immiscible in water, not miscible.
- C. Correct. Ethanol forms an azeotrope with water, so they can be separated by azeotropic distillation.
- D. Correct. A pure organic compound will have the same melting point when mixed with the same compound.
The most appropriate answer is A, C, D only.
Qualitative and Quantitative Analysis of Organic Compounds Question 9:
While preparing crystals of Mohr's salt, dil. H2SO4 is added to a mixture of ferrous sulphate and ammonium sulphate, before dissolving this mixture in water, dil. H2SO4 is added here to:
Answer (Detailed Solution Below)
Qualitative and Quantitative Analysis of Organic Compounds Question 9 Detailed Solution
CONCEPT:
Preparation of Mohr's Salt
- Mohr's salt is a double salt with the chemical formula FeSO4·(NH4)2SO4·6H2O.
- During the preparation of Mohr's salt, it is important to maintain the Fe2+ ions in the ferrous state by preventing their oxidation and hydrolysis.
- Adding dilute sulfuric acid (H2SO4) helps in preventing the hydrolysis of ferrous sulfate and keeps the solution acidic.
EXPLANATION:
Fe+2 ions undergoes hydrolysis, therefore while preparing aqueous solution of ferrous sulphate and ammonium sulphate in water dilute sulphuric acid is added to prevent hydrolysis of ferrous sulphate.
- Hydrolysis of ferrous sulfate can lead to the formation of Fe(OH)2, which can precipitate out of the solution.
- Dilute sulfuric acid prevents this hydrolysis by maintaining an acidic environment, which keeps the ferrous ions in solution.
The correct answer is 1) prevent the hydrolysis of ferrous sulphate.
Qualitative and Quantitative Analysis of Organic Compounds Question 10:
Number of metal ions characterized by flame test among the following is _______.
Sr2+, Ba2+, Ca2+, Cu2+, Zn2+, Co2+, Fe2+
Answer (Detailed Solution Below) 4
Qualitative and Quantitative Analysis of Organic Compounds Question 10 Detailed Solution
CONCEPT:
Flame Test for Metal Ions
- The flame test is a qualitative analysis technique used to detect the presence of certain metal ions based on the color they produce in a flame.
- Different metal ions produce characteristic colors when heated in a flame due to the excitation of electrons and the subsequent emission of light at specific wavelengths.
Key Points
- Sr2+ (Strontium Ion):
- Produces a crimson (red) flame.
- Ba2+ (Barium Ion):
- Produces a green flame.
- Ca2+ (Calcium Ion):
- Produces a brick-red flame.
- Cu2+ (Copper Ion):
- Produces a green or blue-green flame.
- Zn2+ (Zinc Ion):
- Produces a bluish-green flame, but this is often faint and not always reliable for identification.
- Co2+ (Cobalt Ion):
- Does not produce a characteristic flame color and is not typically identified by flame test.
- Fe2+ (Iron Ion):
- Does not produce a characteristic flame color and is not typically identified by flame test.
Conclusion:-
The metal ions that can be characterized by the flame test from the given list are:
Sr2+, Ba2+, Ca2+, and Cu2+. Total number of metal ions characterized by the flame test = 4