Named Reactions MCQ Quiz in मराठी - Objective Question with Answer for Named Reactions - मोफत PDF डाउनलोड करा

Last updated on Mar 19, 2025

पाईये Named Reactions उत्तरे आणि तपशीलवार उपायांसह एकाधिक निवड प्रश्न (MCQ क्विझ). हे मोफत डाउनलोड करा Named Reactions एमसीक्यू क्विझ पीडीएफ आणि बँकिंग, एसएससी, रेल्वे, यूपीएससी, स्टेट पीएससी यासारख्या तुमच्या आगामी परीक्षांची तयारी करा.

Latest Named Reactions MCQ Objective Questions

Top Named Reactions MCQ Objective Questions

Named Reactions Question 1:

The major product of this reaction is :

qImage671d0a620aad96f1b0715325Task Id 919 Daman (1)

  1. F1 Savita Teaching 8-4-24 D2
  2. F1 Savita Teaching 8-4-24 D4
  3. F1 Savita Teaching 8-4-24 D3
  4. F1 Savita Teaching 8-4-24 D5

Answer (Detailed Solution Below)

Option 2 : F1 Savita Teaching 8-4-24 D4

Named Reactions Question 1 Detailed Solution

The correct answer is option 2

Explanation:-

The mechanism is as follows:

  • Deprotonation: The first step shows a ketone being deprotonated by a strong base, potassium hydride (KH), to form an enolate ion. The electron pair on the oxygen of the enolate then delocalizes to form a resonance-stabilized enolate with the negative charge on the carbon atom.
  • Nucleophilic Attack: In the second step, this enolate ion acts as a nucleophile and attacks a nitro alkene (presumably formed in a separate reaction not shown in the image), resulting in the addition of the enolate to the beta position of the nitro alkene. This forms a new carbon-carbon bond.
  • Protonation: Following the nucleophilic attack, the intermediate is protonated to form a ketone with an adjacent nitro group.
  • Nucleophilic Substitution (SN2): The nitro group positioned next to the ketone is then replaced by a nucleophile (Nu) through an SN2 reaction. This is typically characterized by a backside attack of the nucleophile, leading to the inversion of configuration at the carbon atom, and the departure of the leaving group.
  • Reduction: The final step is the reduction of the nitro group to an amine. This is achieved by treatment with zinc/ammonium chloride (Zn/Ammonium chloride), which reduces the nitro group first to a nitroso group (N=O), and subsequently to an oxime (N-OH), and finally to an amine (NH2). The oxime may also isomerize to an imine before the final reduction to the amine.

qImage671d0a630aad96f1b0715327Task Id 919 Daman (2)

Conclusion:-

So, the final product will be option 2.

Named Reactions Question 2:

The major product of the reaction is

F1 Teaching Arbaz 7-11-23 D7

  1. F1 Teaching Arbaz 7-11-23 D8
  2. F1 Teaching Arbaz 7-11-23 D9
  3. F1 Teaching Arbaz 7-11-23 D10
  4. F1 Teaching Arbaz 7-11-23 D11

Answer (Detailed Solution Below)

Option 1 : F1 Teaching Arbaz 7-11-23 D8

Named Reactions Question 2 Detailed Solution

Concept:-

Diels–Alder reaction:

  • Diels–Alder reactions occur between a conjugated diene and an alkene, usually called the dienophile.
  • This reaction goes in a single step simply on heating.
  • Here are some examples: first an open-chain diene with a simple unsaturated aldehyde as the dienophile

F2 Savita Teaching 19-5-23 D41

Diene:

  • The diene component in the Diels–Alder reaction can be open-chain or cyclic and can have many different substituents.
  • There is only one limitation: The diene must have the s-cis conformation.
  • Butadiene typically prefers the s-trans conformation with the two double bonds as far away from each other as possible for steric reasons. The barrier to rotation about the central σ bond is small (about 30 kJ.mol−1 at room temperature) and rotation to the less favorable but reactive s-cis conformation is rapid.

F2 Savita Teaching 19-5-23 D42

  • Cyclic dienes that are permanently in the s-cis conformation are exceptionally good at Diels–Alder reactions—cyclopentadiene is a classic example—but cyclic dienes that are permanently in the s-trans conformation and cannot adopt the s-cis conformation will not do the
    Diels–Alder reaction at all.
  • Dienes permanently in the s-cis conformation are excellent for Diels–Alder reactions.

F2 Savita Teaching 19-5-23 D43

  • The Approach of dienophile from the below and the above of the diene plane is shown below:

F1 Teaching Arbaz 7-11-23 D12

F1 Teaching Arbaz 7-11-23 D13

Explanation:-

  • The reaction pathway is shown below:

F1 Teaching Arbaz 7-11-23 D14

Conclusion:-

  • Hence, the major product of the reaction is

F1 Teaching Arbaz 7-11-23 D8

Named Reactions Question 3:

The major product formed in the following reaction is

F1 Savita Teaching 2-6-23 D3

  1. F1 Savita Teaching 2-6-23 D4
  2. F1 Savita Teaching 2-6-23 D5
  3. F1 Savita Teaching 2-6-23 D6
  4. F1 Savita Teaching 2-6-23 D7

Answer (Detailed Solution Below)

Option 4 : F1 Savita Teaching 2-6-23 D7

Named Reactions Question 3 Detailed Solution

Explanation:-

The Chugaev Reaction

  • The reaction pathway is shown below:

F1 Savita Teaching 2-6-23 D8

  • The loss of C(O)S and MeSH occur at lower ternperatures than the carboxylic ester pyrolysis and thus is rnore suitable for the preparation of sensitive alkenes.
  • Heating the xanthate derived by sequential treatment of cis-2-benzylcyclopentan with sodium in toluene followed by addition of excess carbon disulfide and methyl iodide furnishes, via a syn-elimination, 3-benzylcyclopentene.

Conclusion:-

  • Hence, the major product formed in the following reaction is

F1 Savita Teaching 2-6-23 D7

Named Reactions Question 4:

The major product formed in the following reaction is 

F1 Savita Teaching 30-5-23 D35

  1. F1 Savita Teaching 30-5-23 D36
  2. F1 Savita Teaching 30-5-23 D37
  3. F1 Savita Teaching 30-5-23 D38
  4. F1 Savita Teaching 30-5-23 D39

Answer (Detailed Solution Below)

Option 3 : F1 Savita Teaching 30-5-23 D38

Named Reactions Question 4 Detailed Solution

Concept:

  • In an aldol reaction, the enolate of an aldehyde or a ketone reacts at the α-carbon atom with the carbonyl of another molecule under basic or acidic conditions to obtain a β-hydroxy carbonyl compound.
  • The mechanism of the aldol reaction is shown below:

F2 Madhuri Teaching 27.03.2023 D131

  • The intramolecular aldol reaction is the condensation reaction of two aldehyde groups or ketone groups in the same molecule in presence of a base.
  • An example is shown below:

F2 Madhuri Teaching 27.03.2023 D87

Explanation:-

  • The reaction pathway is shown below:

F1 Savita Teaching 30-5-23 D40

Conclusion:-

Hence, the major product formed in the following reaction is

F1 Savita Teaching 30-5-23 D38

Named Reactions Question 5:

The major product of the following reaction is
F2 Vinanti Teaching 27.04.23 D61

  1. F2 Vinanti Teaching 27.04.23 D62
  2. F2 Vinanti Teaching 27.04.23 D63
  3. F2 Vinanti Teaching 27.04.23 D64
  4. F2 Vinanti Teaching 27.04.23 D65

Answer (Detailed Solution Below)

Option 4 : F2 Vinanti Teaching 27.04.23 D65

Named Reactions Question 5 Detailed Solution

Concept:-

 Corey–Winter reaction:

  • Elimination of thionocarbonates is termed the Corey–Winter reaction.
  • Attack by the phosphorus reagent on the sulfur atom is followed by fragmentation to give the alkene.

F2 Vinanti Teaching 27.04.23 D66
Explanation:-

  • The reaction pathway is shown below
    F2 Vinanti Teaching 27.04.23 D67

Conclusion:-

  • Hence, option 4 is the correct answer.

Named Reactions Question 6:

The major product in the following reaction is
F2 Vinanti Teaching 27.04.23 D105

  1. F2 Vinanti Teaching 27.04.23 D106
  2. F2 Vinanti Teaching 27.04.23 D107
  3. F2 Vinanti Teaching 27.04.23 D108
  4. F2 Vinanti Teaching 27.04.23 D109

Answer (Detailed Solution Below)

Option 4 : F2 Vinanti Teaching 27.04.23 D109

Named Reactions Question 6 Detailed Solution

Concept:-

Aldol Condensation:

  • In an aldol reaction, the enolate of an aldehyde or a ketone reacts at the α-carbon atom with the carbonyl of another molecule under basic or acidic conditions to obtain a β-hydroxy carbonyl compound.
  • The mechanism of the aldol reaction is shown below:
    F2 Vinanti Teaching 27.04.23 D110

Explanation:-

  • The mechanism of the reaction is shown below:
    F2 Vinanti Teaching 27.04.23 D111
  • Complete selectivity occurs for one of the two possible syn aldol products, the choice of the syn product being made by the choice of the chiral auxiliary group.
  • The stereoselectivity can be rationalized by a six-membered (Zimmerman–Traxler) transition state, in which the aldehyde approaches from
    the less-hindered face.

F2 Vinanti Teaching 27.04.23 D112
Conclusion:-

  • Hence, option 4 is the correct answer.

Named Reactions Question 7:

Identify Name Reaction 

F1 Savita Teaching 28-6-23 D12

  1. Pauson-Khand
  2. Payne
  3. Pearlman
  4. Paterno-Buchi

Answer (Detailed Solution Below)

Option 4 : Paterno-Buchi

Named Reactions Question 7 Detailed Solution

Explanation:-

  • The Pauson–Khand reaction (or PKR or PK-type reaction) is a chemical reaction described as a [2+2+1] cycloaddition between an alkyne, an alkene, and carbon monoxide to form an α,β-cyclopentenone.
  • An example is given below:

F1 Savita Teaching 28-06-23 D13
 

  • The Payne rearrangement is the isomerization, under basic conditions, of 2,3-epoxy alcohols to isomeric 1,2-epoxy alcohols with inversion of configuration.
  • An example is given below:

F1 Savita Teaching 28-6-23 D31

  • The Paternò–Büchi reaction, named after Emanuele Paternò and George Büchi, who established its basic utility and is a photochemical reaction, specifically a [2+2] photocycloaddition, which forms four-membered oxetane rings from an excited carbonyl and reacting with an alkene.
  • An example is given below:

F1 Savita Teaching 28-6-23 D14

  • Thus, the given reaction is an example of the Paterno-Buchi reaction.

Conclusion:-

  • Hence, it is Paterno-Buchi reaction.

Named Reactions Question 8:

Identify the product formed in the following transformations
F1 Vinanti Teaching 30.03.23 D14

  1. F1 Vinanti Teaching 30.03.23 D15
  2. F1 Vinanti Teaching 30.03.23 D16
  3. F1 Vinanti Teaching 30.03.23 D17
  4. F1 Vinanti Teaching 30.03.23 D18

Answer (Detailed Solution Below)

Option 1 : F1 Vinanti Teaching 30.03.23 D15

Named Reactions Question 8 Detailed Solution

Explanation:-

  • The reaction pathway is shown below:

qImage649298fe21b36ea1b6277c35

Conclusion:-

  • Hence,  the product formed in the following transformations is

F1 Vinanti Teaching 30.03.23 D15

Named Reactions Question 9:

The major product formed in the following reaction

F1 Madhuri Teaching 06.02.2023 D35

  1. F1 Madhuri Teaching 06.02.2023 D36
  2. F1 Madhuri Teaching 06.02.2023 D37
  3. F1 Madhuri Teaching 06.02.2023 D38
  4. F1 Madhuri Teaching 06.02.2023 D39

Answer (Detailed Solution Below)

Option 2 : F1 Madhuri Teaching 06.02.2023 D37

Named Reactions Question 9 Detailed Solution

Explanation: -

The reaction will involve the following steps: -

Step 1: Oxidative-addition i.e. addition of organic compound on metal complex via sigma complex state with an increase in oxidation state on the metal ion.

F1 Madhuri Teaching 06.02.2023 D40

Step 2: Transmetalation rearrangement reaction, this reaction involves the transfer of ligands from one metal to another metal complex.

F1 Madhuri Teaching 06.02.2023 D41

Step 3: Reduction-elimination reaction, in this reaction metal, will undergo reduction by two oxidation states and two of the ligand will leave and form a single molecular species.

F1 Madhuri Teaching 06.02.2023 D42

Conclusion: -

The reaction will produce the product preserved stereochemistry as follows: -

F1 Madhuri Teaching 06.02.2023 D43

Hence, The correct option is - 2.

Named Reactions Question 10:

The major product in the given reaction is:

qImage679cb9bd81632c69d413e8e0

  1. qImage679cb9bd81632c69d413e8ed
  2. qImage679cb9be81632c69d413e8ee
  3. qImage679cb9be81632c69d413e8f1
  4. qImage679cb9bf81632c69d413e8f2

Answer (Detailed Solution Below)

Option 3 : qImage679cb9be81632c69d413e8f1

Named Reactions Question 10 Detailed Solution

Concept:

Appel Reaction

Appel reaction remains a valuable tool for the synthesis of alkyl halides, particularly for sensitive alcohols. However, ongoing research is focused on addressing its limitations and developing more sustainable alternatives.

  • The reaction typically employs triphenylphosphine (PPh3) and tetrahalomethane (CX4, where X = Cl, Br, or I).
  • Carbon tetrachloride (CCl4) is commonly used for synthesizing alkyl chlorides, while carbon tetrabromide (CBr4) or bromine (Br2) can be used for alkyl bromides, and carbon tetraiodide (CI4) or iodine (I2) for alkyl iodides. 

Explanation:

General Mechanism

qImage679cb9bf81632c69d413e8f3

qImage679cb9bf81632c69d413e8f4

Therefore, the correct option is 3.

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