CSAT MCQ Quiz in मल्याळम - Objective Question with Answer for CSAT - സൗജന്യ PDF ഡൗൺലോഡ് ചെയ്യുക
Last updated on Apr 9, 2025
Latest CSAT MCQ Objective Questions
Top CSAT MCQ Objective Questions
CSAT Question 1:
If February 1, 1996, is Wednesday, what day is March 3, 1996?
Answer (Detailed Solution Below)
CSAT Question 1 Detailed Solution
The Correct answer is Option 3
Key PointsFebruary 1996 is a leap year
⇒ Since 1996 is divisible by 4, it is a leap year. This means February has 29 days.
Count the days from February 1 to March 3
⇒ Days remaining in February:
⇒ February has 29 days.
⇒ From February 1 (Wednesday) to February 29:
⇒ Total days = 28 days after February 1.
⇒ Divide by 7 (week cycle): 28÷7=4 weeks.
⇒ Hence, February 29 is also Wednesday.
Count days in March up to March 3:
⇒ March 1: Thursday (1 day after Wednesday),
⇒ March 2: Friday,
⇒ March 3: Saturday.
⇒ March 3, 1996, is Saturday.
Hence Correct answer is Option 3.
CSAT Question 2:
What is the 14th term of the sequence 14, 10, 6, 2...?
Answer (Detailed Solution Below)
CSAT Question 2 Detailed Solution
The Correct answer is Option 4.
Key Points⇒ The sequence decreases by −4 each time.
⇒ The formula for the n-th term of an AP is: an = a1 + (n-1) .d
⇒ Here, a1 = 14 , d = -4 , n = 14
⇒ a14 =14 + (14−1)(−4) = 14 − 52 = −38.
Hence Option 4 is correct.
CSAT Question 3:
What should come in place of the question mark (?) in the following sequence:
Answer (Detailed Solution Below)
CSAT Question 3 Detailed Solution
The Correct answer is Option 1.
Key Points First We need to Understand through logic
In Figure :
⇒ Difference between upper Two digits is equal to difference between below Two Digits
⇒ 21 - 16 = 5 , 15 - 10 = 5 (Both Equal)
⇒ 10 - 7 = 3 , 13 - 10 = 3
⇒ Hence 21 - 14 = 7 , Means Difference between upper digit in last figure also be same
⇒ ? - 15 = 7 ⇒ ? = 22
Hence Option 1 is correct.
CSAT Question 4:
If
6 ⊕ 8 = 10
7 ⊕ 12 = 15
9 ⊕ 15 = 20
10 ⊕ 14 = 20
what is the value of 12 ⊕ 16 ⊕ 9?
Answer (Detailed Solution Below)
CSAT Question 4 Detailed Solution
Calculation:
⇒ 6 ⊕ 8 = 10
6 + 8 = 14
14 − 4 = 10
⇒ 7 ⊕ 12 = 15
7 + 12 = 19
19 − 4 = 15
⇒ 9 ⊕ 15 = 20
9 + 15 = 24
24 − 4 = 20
⇒ 10 ⊕ 14 = 20
10 + 14 = 24
24 − 4 = 20
Hence,
⇒ 12 ⊕ 16 ⊕ 9
12 + 16 + 9 = 37
37 - 4 = 33
Hence, the Correct answer is Option 4.
CSAT Question 5:
A rectangular floor measures 5 m in length and 3 m in breadth. Tiles of size 150 cm by 75 cm have to be laid such that the tiles do not overlap. A tile can be placed in any orientation so long as its edges are parallel to the edges of the floor. What is the maximum number of tiles that can be accommodated on the floor?
Answer (Detailed Solution Below)
CSAT Question 5 Detailed Solution
The Correct answer is Option 2.
Key PointsStep 1: Convert the dimensions of the floor and the tiles to the same units:
- Floor dimensions: 5 m × 3 m = 500 cm × 300 cm.
- Tile dimensions: 150 cm × 75 cm.
Step 2: Calculate the area of the floor and the tiles:
- Area of the floor: 500 cm × 300 cm = 150,000 cm2.
- Area of one tile: 150 cm × 75 cm = 11,250 cm2.
Step 3: Determine how many tiles fit on the floor:
- Number of tiles that fit in the 500 cm length: 500 cm ÷ 150 cm = 3 (since only whole tiles are allowed).
- Number of tiles that fit in the 300 cm breadth: 300 cm ÷ 75 cm = 4.
Step 4: Calculate the total number of tiles:
- Total number of tiles = 3 × 4 = 12.
Hence Correct answer is Option 2 — 12.
CSAT Question 6:
Out of a class of 100 students, 25 play at least cricket and football, 15 play at least cricket and hockey, 12 play at least football and hockey and 10 play all the three sports. The number of students playing cricket, football and hockey are 50, 37, and 22, respectively. The number of students who do NOT play any of the three sports is
Answer (Detailed Solution Below)
CSAT Question 6 Detailed Solution
The Correct answer is Option 1.
Key PointsTo find the number of students who do not play any of the three sports (cricket, football, and hockey), we can use the principle of inclusion-exclusion.
Step 1: Define the sets
- C = number of students playing cricket = 50
- F = number of students playing football = 37
- H = number of students playing hockey = 22
- |C ∩ F| = number of students playing at least cricket and football = 25
- |C ∩ H| = number of students playing at least cricket and hockey = 15
- |F ∩ H| = number of students playing at least football and hockey = 12
- |C ∩ F ∩ H| = number of students playing all three sports = 10
Step 2: Use the inclusion-exclusion principle
⇒ The formula for the number of students playing at least one of the sports is: |C ∪ F ∪ H| = |C| + |F| + |H| - |C ∩ F| - |C ∩ H| - |F ∩ H| + |C ∩ F ∩ H|
Step 3: Substitute the values
⇒ Substituting the values into the formula: |C ∪ F ∪ H| = 50 + 37 + 22 - 25 - 15 - 12 + 10
Calculating step by step:
- Sum of individual sports: 50 + 37 + 22 = 109
- Sum of pairwise intersections: 25 + 15 + 12 = 52
- Now substitute: |C ∪ F ∪ H| = 109 - 52 + 10 = 67
Step 4: Calculate the number of students not playing any sports
The total number of students is 100. Therefore, the number of students who do not play any of the three sports is: Students not playing any sport = 100 - |C ∪ F ∪ H| = 100 - 67 = 33
Thus, the number of students who do not play any of the three sports is: 1) 33
CSAT Question 7:
Which of the following statements is/are correct?
1. The average of four numbers 10, 15, 20 and 25 is 17.5
2. If a, b and c are three different such that natural numbers a + b + c = abc, then the average of a, b and c is 3
Select the answer using the code given below:
Answer (Detailed Solution Below)
CSAT Question 7 Detailed Solution
The correct answer is Option 1
Key PointsStatement 1: The average of four numbers 10, 15, 20, and 25 is 17.5.
⇒ To find the average, we use the formula: Average = Sum of numbers / Number of numbers
⇒ Calculating the sum: 10+15+20+25=70
⇒ Now, calculating the average: Average=70/4=17.5
Conclusion: Statement 1 is correct.
Statement 2: If a, b, and c are three different natural numbers such that a+b+c=abc then the average of a, b, and c is 3.
⇒ Let's analyze the equation a+b+c=abc
⇒ If we assume a,b,c are the smallest natural numbers that satisfy this equation, we can try a=1,b=2,c=3
⇒ 1+2+3=6 and 1×2×3=6
This satisfies the equation.
⇒ Now, calculating the average: 1 + 2 + 3 / 3 = 6/3 = 2
Conclusion: Statement 2 is incorrect because the average is 2, not 3.
Final Conclusion:
Statement 1 is correct.
Statement 2 is incorrect.
Thus, the correct answer is: 1 only
CSAT Question 8:
Household finance in India is unique. We have a tendency to invest heavily in physical assets such as gold and property. Steps to encourage the financialization of savings are critical. A populace accustomed to traditional processes will not simply jump into financialization. Hurdles to change include onerous bureaucracy, a scepticism of organized financial institutions, a lack of basic information about which of the myriad basic information about which of the myriad services and providers is best for each family, and how (and even if) one can make the transition between them if necessary.
Regarding the financialization of household savings, which of the following statements best reflect the solutions that are implied by the passage?
1. A flexible environment is needed to develop solutions.
2. Households need customised solutions.
3. Innovations in financial technology are required.
Select the correct answer using the code given below:
Answer (Detailed Solution Below)
CSAT Question 8 Detailed Solution
- The passage emphasizes the need for adapting the financial system to fit the unique preferences and hurdles faced by Indian households, implying the need for flexible solutions (Option 1).
- It mentions the challenges in choosing the right services and providers, indicating the necessity of personalized, or customised, solutions for each household (Option 2).
- The hurdles mentioned, such as bureaucracy, skepticism towards financial institutions, and a lack of information, suggest that innovations in financial technology could help overcome these barriers by simplifying processes and increasing transparency (Option 3).
- All three points addressed are implied as part of the solution to encourage the financialization of household savings in India, making Options 1, 2, and 3 relevant.
- The passage discusses barriers that prevent households from transitioning into more financialized savings, implicitly suggesting that overcoming these barriers requires a combination of flexibility, customization, and technological innovation.
- A flexible environment (Option 1) is necessary to adapt to the diverse needs and preferences of households, which vary widely across different regions and demographics.
- Customised solutions (Option 2) are important because of the varying financial literacy levels, risk appetites, and financial goals among Indian households. Tailored advice and products can help address these individual needs more effectively.
- Innovations in financial technology (Option 3) can streamline processes, reduce paperwork, enhance security, and provide easier access to financial information, making it simpler for households to navigate and trust the financial system.
- The passage does not explicitly mention these solutions, but they are implied as ways to address the challenges outlined, making all three options correct in context.
CSAT Question 9:
What in the maximum value of n such that 7 × 343 × 385 × 1000 × 2401 × 77777 is divisible by 35n ?
Answer (Detailed Solution Below)
CSAT Question 9 Detailed Solution
The Correct answer is Option 2
Key Points
35n = 7n × 5n
The given expression: 7 × 343 × 385 × 1000 × 2401 × 77777 =
7 × 73 × (5 × 7 × 11) × (23 × 53)× 74 × (7 × 11111) = 710 × 54 × ……
The lower power will determine the value of n, i.e. 54 . As the power of 5 in the expression is 4, the maximum value of n would also be 4.
Hence Correct answer is Option 2.
CSAT Question 10:
Product of sum of the cubes of first 4 natural numbers‘ and first even natural number‘ is –
Answer (Detailed Solution Below)
CSAT Question 10 Detailed Solution
The Correct answer is Option 3.
Key Points
Sum of the cubes of first 4 natural numbers = 13 + 23 + 33 + 43
= 1 + 8 + 27 + 64 = 100
First even natural number = 2
Required product = 2 × 100 = 200
Hence Correct answer is Option 3.