Water Requirement of Crops MCQ Quiz - Objective Question with Answer for Water Requirement of Crops - Download Free PDF

Last updated on Jun 19, 2025

Latest Water Requirement of Crops MCQ Objective Questions

Water Requirement of Crops Question 1:

If duty is 1428 hectares/cumec and base period is 120 days for an irrigated crop, then the delta in meters is given by

  1. 1.381
  2. 0.017
  3. 0.726
  4. 102.805

Answer (Detailed Solution Below)

Option 3 : 0.726

Water Requirement of Crops Question 1 Detailed Solution

Concept:

The relation between duty, base period and delta is given by:

\(\Delta=\frac{8.64 \times B}{D}\)

Calculation:

B = 120 days

D = 1428 hectares/cumec

\(\Delta=\frac{8.64 \times 120}{1428}=0.726m\)

Water Requirement of Crops Question 2:

The total area which can be economically irrigated from an irrigation system without considering the limitation of the quantity of water available

  1. Gross Command Area
  2. Culturable Command Area
  3. Gross Cultivable Area
  4. Mean sea level

Answer (Detailed Solution Below)

Option 1 : Gross Command Area

Water Requirement of Crops Question 2 Detailed Solution

Explanation:

Gross Command Area (GCA):

  • It is the total area that can be economically irrigated from an irrigation system, irrespective of water availability.

  • It includes all land types within the command — both cultivable and uncultivable (roads, settlements, barren lands, etc.).

  • It forms the basis for further classifications like Culturable Command Area and Net Irrigated Area.

 Additional Information

Culturable Command Area (CCA):

  • Part of the Gross Command Area that is suitable for cultivation.

  • Excludes uncultivable land such as forests, rocky terrain, and infrastructure.

  • Water availability is also not a limiting factor in its definition.

Gross Cultivable Area:

  • Refers to the total cultivable land in a region, which may not be linked to a specific irrigation system.

  • It includes both rain-fed and irrigated areas.

Mean Sea Level (MSL):

  • A standard reference for measuring elevations and altitudes.

  • It has no relevance in defining irrigable command areas.

Water Requirement of Crops Question 3:

Wheat is to be grown in a field having field capacity equal to 30% and the permanent wilting point equal to 10%. Irrigation water is to be supplied when the moisture content of the soil falls to 20%. The root zone depth is 1 m , dry weight of soil is 14 kN/mand the specific weight of water is 10 kN/m3. The Net Irrigation Requirement (NIR) for the above cultivation is:

  1. 28 cm of water
  2. 19.6 cm of water
  3. 21 cm of water
  4. 14 cm of water

Answer (Detailed Solution Below)

Option 4 : 14 cm of water

Water Requirement of Crops Question 3 Detailed Solution

Concept:

  • Net Irrigation Requirement (NIR) is the depth of water required to restore the soil moisture in the root zone to field capacity after depletion.

  • It is calculated as the difference between moisture at field capacity (FC) and moisture at the time of irrigation, multiplied by root zone depth and adjusted for the weight of soil and water.

\(NIR=(FC-MC)\times RootZoneDepth\times\frac{\gamma_d}{\gamma_w}\)

where:
FC = Field Capacity (%),
MC = Moisture content at time of irrigation (%),
\(\gamma_d\) = Dry unit weight of soil (kN/m³),
\(\gamma_w\) = Unit weight of water (kN/m³).

Calculation:

Given:
Field Capacity (FC) = 30%
Permanent Wilting Point (PWP) = 10%
Moisture at time of irrigation (MC) = 20%
Root zone depth = 1 m = 1000 mm
\(γ_d = 14 kN/m³\)
\(γ_w = 10 kN/m³\)

\(NIR=(30-20)\times1\times\frac{14}{10}\)

\(NIR=10\times1\times1.4=14cm\)

Water Requirement of Crops Question 4:

Out of 120 cm of water pumped into a canal, 80 cu m of water could be supplied to a field. 60 cu m of water was stored in the root zone while water required in root zone prior to irrigation was 80 cu m. The storage efficiency of irrigation is

  1. 75%
  2. 50%
  3. 100%
  4. 66.67%

Answer (Detailed Solution Below)

Option 1 : 75%

Water Requirement of Crops Question 4 Detailed Solution

Concept: 

Storage Efficiency of Irrigation

It is a measure of how effectively water is stored in the root zone during irrigation compared to the amount of water that was required in the root zone before irrigation. It is calculated using the ratio of water store to the water required, expressed as a percentage.

Calculations:

Given: Water stored in the root zone = 60 cum

Water required in the root zone prior to irrigation = 80 cum

Storage efficiency = (60/80) x 100 % = 75 %

Water Requirement of Crops Question 5:

Time factor for rabi season is fixed at 0.75 for a canal. What are the number of days for which a distributary will receive its full supply if the crop season is 120 days?

  1. 50 days
  2. 90 days
  3. 30 days
  4. 110 days
  5. None of the above

Answer (Detailed Solution Below)

Option 2 : 90 days

Water Requirement of Crops Question 5 Detailed Solution

Concept:

Time factor: 

It is the ratio of no. of days canal has actually run during a watering period to that of no. of days of watering period.

Calculation:

Given:

Time factor = 0.75

Watering period = 120 days

The number of days for which a distributary will receive full is  0.75 × 120 = 90 days.

Top Water Requirement of Crops MCQ Objective Questions

What is the relation between Consumptive Irrigation Requirement (CIR), Net Irrigation Requirement (NIR), Field Irrigation Requirement (FIR) and Gross Irrigation Requirement (GIR)?

  1. CIR>FIR>GIR>NIR
  2. CIR>GIR>FIR>NIR
  3. GIR>FIR>CIR>NIR
  4. GIR>FIR>NIR>CIR

Answer (Detailed Solution Below)

Option 4 : GIR>FIR>NIR>CIR

Water Requirement of Crops Question 6 Detailed Solution

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Explanation

We know,

a) Consumptive Irrigation Requirements (CIR) = Consumptive Use (Cu) – Effective Rainfall (Re)

b) Net Irrigation Requirement (NIR) = CIR + other requirements such as leaching

c) Field Irrigation Requirements (FIR) = NIR + Surface runoff losses + deep percolation losses

Or

\({\rm{FIR}} = \frac{{{\rm{NIR}}}}{{{\rm{Water\;application\;efficiency}}}}\)

d) Gross Irrigation Requirements (GIR) = FIR + Conveyance Losses (Seepage and Evaporation)

Or 

\({\rm{GIR}} = \frac{{{\rm{FIR}}}}{{{\rm{Water\;Conveyance\;efficiency}}}}\)

If you look through the above equations we can conclude that

 GIR > FIR, FIR > NIR, NIR > CIR 

∴ GIR > FIR > NIR > CIR

Calculate the water distribution efficiency, if the depths of penetration along the length of a border strip at an interval of 20 m are 1.5 m, 1.8 m and 2.1 m respectively.

  1. 0.6667
  2. 0.8333
  3. 0.8889
  4. 0.9767

Answer (Detailed Solution Below)

Option 3 : 0.8889

Water Requirement of Crops Question 7 Detailed Solution

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Concept:

Water distribution efficiency \(= {{\rm{\eta }}_{\rm{d}}} = \left[ {1 - \frac{{\rm{y}}}{{{{\rm{d}}_{\rm{w}}}}}} \right] \times 100{\rm{\;}}\left( {{\rm{in\;\% }}} \right)\)

\({{\rm{d}}_{\rm{w}}} = \frac{{{{\rm{d}}_1} + {{\rm{d}}_2} + \ldots + {{\rm{d}}_{\rm{n}}}}}{{\rm{n}}},\) dw = average depth of water stored

\({\rm{y}} = \frac{{y_1 \ + \ y_2\ + \ ......\ +\ y_n}}{n}\), y = Average of absolute value of deviations

y1, y2,......., yn = absolute deviations from average depth of water stored

Calculation:

\({\rm{d_w}} = \frac{{1.5 + 1.8 + 2.1}}{3} = 1.8\)

y1 = 0.3 m, y2 = 1.8 – 1.8 = 0, y3 = 2.1 – 1.8 = 0.3 m

\({\rm{y}} = \frac{{0.3 + 0.3 + 0}}{3} = 0.2\)

\({{\rm{\eta }}_{\rm{d}}} = \left( {1 - \frac{{0.2}}{{1.8}}} \right) = \frac{8}{9} = 0.8889\)

What is the variation in duty of water from the head of a main canal (M) to that in the field (F)?

  1. ​Duty of water at M is always greater than duty of water at F
  2. ​Duty of water at M is always less than duty of water at F
  3. Duty of water at M is always equal to duty of water at F
  4. Duty of water at M can be greater or less than duty of water at F

Answer (Detailed Solution Below)

Option 2 : ​Duty of water at M is always less than duty of water at F

Water Requirement of Crops Question 8 Detailed Solution

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Duty: It is the number of hectares of land irrigated for full growth of a given crop by a supply of 1 cumec of water continuously during the entire base period of that crop.

Duty of water changes from place to place, it will be maximum at the field and minimum at the head of the main canal.

Duty is the area that can be irrigated by the discharge of 1 cumec of water.

At the head of the canal, there are numerous losses to occur later which requires more amount of water to irrigate a particular field. However, if considered on the field, all losses have already occurred and a lesser amount of water is required to irrigate the same considered area.

F1 N.M M.P 22.07.19 D 1

The field capacity of a soil is 25%, its permanent wilting point is 15% and specific dry unit weight is 1.5 g/cc. If the depth of the root zone of a crop is 80 cm, the storage capacity of the soil is

  1. 8 cm
  2. 10 cm
  3. 12 cm
  4. 14 cm

Answer (Detailed Solution Below)

Option 3 : 12 cm

Water Requirement of Crops Question 9 Detailed Solution

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Concept:

For an irrigation land:

Assignment 3 Subham SSC JE CE 24 JAN 18 Evening 9Q shubham D 1

SC = Saturation capacity, FC = Field capacity, OMC = Optimum moisture content, PWP = Permanent welting point and UWP = Ultimate welting point

1. Equivalent depth of water held at field capacity (x) = S × d × Fc

2. Equivalent depth of water held at PWP (x’) = S × d × (PWP)

3. Available moisture/storage capacity of soil (y) = S × d × (Fc - PWP)

4. Readily available moisture content (dw) = S × d × (Fc - OMC)

Given:

Field capacity (F. C) = 25 % = 0.25

Permanent willing point (PWP) = 15 % = 0.15

Depth of the root zone (d) = 80 cm

Dry Unit weight of soil (γd) = 1.5 g/cc

Calculations:

The storage capacity \(= \frac{{{\gamma _d} \times d \times \left( {F.C - PWP} \right)}}{{{\gamma _w}}}\)

The storage capacity \(= \frac{{1.5 \times 80 \times \left( {0.25 - 0.15} \right)}}{1} = 12\;cm\)

Hence, the storage capacity of the soil is 12 cm.

The soil having electrical conductivity less than 4000 micro-ohms/cm at 25˚C and exchangeable sodium percentage greater than 15 and pH between 8.5 -10.0 is called

  1. Saline soil
  2. Alkali soil
  3. Saline-alkali soil
  4. Normal soil

Answer (Detailed Solution Below)

Option 2 : Alkali soil

Water Requirement of Crops Question 10 Detailed Solution

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Explanation:

Alkali or alkaline soil:

  • Alkaline soils are clay soils with high pH (> 8.5), a poor soil structure, and a low infiltration capacity. 
  • it usually contains a great deal of sodium, calcium, and magnesium ions.
  • Alkaline soil is less soluble than acidic or neutral soil, availability of nutrients is often limited.
  • In arid or desert areas where rainfall is slim and places where there are dense forests, soil tends to be more alkaline.

Classification of different types of soil:

Classification

Electrical Conductivity (micro-ohms/cm)

Exchangeable Sodium Percentage (ESP)

pH

Saline

> 4000

< 15

< 8.5

Alkaline

< 4000

> 15

8.5-10

Saline-alkaline

> 4000

> 15

< 8.5

The given figure represents ______.

F1 Abhishek M 12.2.21 Pallavi D4

  1. furrow method of irrigation
  2. classes of soil water
  3. base flow of water
  4. frequency of irrigation

Answer (Detailed Solution Below)

Option 4 : frequency of irrigation

Water Requirement of Crops Question 11 Detailed Solution

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Explanation: 

Frequency of irrigation: It is defined as the ratio of available soil moisture depletion to rate of consumptive use. 

Screen Shot 2021-02-18 at 12.00.37 PM

Wilting coefficient: The moisture content at which plant can no longer extract the water from the soil for their growth and finally wilts up, It is known as the wilting coefficient. 

Which of the following is correct about annual irrigation intensity?

  1. It can be greater than 100%
  2. Minimal value of annual irrigation is desirable.
  3. It is the area in percentage of the gross command area irrigated in a season.
  4. It is the area in percentage of the cultural command area irrigated in a season.

Answer (Detailed Solution Below)

Option 1 : It can be greater than 100%

Water Requirement of Crops Question 12 Detailed Solution

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Explanation:

Annual irrigation intensity:

By adding intensities of irrigation for all the crop seasons we obtain the annual intensity of irrigation.

Annual intensity of irrigation can be more than 100%.

The annual irrigation intensity is usually found to be in the range of 40 to 60%. But needs to be raised in the range of 100 to 180% by cultivating larger parts of CCA with more than one crop in a year.

Important Points

Intensity of irrigation is the percentage of Culturable Commanded c (CCA) to be irrigated annually for a particular crop season.

CCA is portion of gross commanded area that is cultivable.

CCA = Gross Command Area – Uncultivable area (pasture lands, ponds, townships, waste land)

A certain crop needs 3 cumec of water for irrigating 5100 hectares land up to 10 cm depth. Total 12 watering at an interval of 10 days are needed. Duty and delta (in hectare/cumec and cm respectively) will be:

  1. 51000, 1200
  2. 15300, 0.12
  3. 1700, 120
  4. 510, 1.2

Answer (Detailed Solution Below)

Option 3 : 1700, 120

Water Requirement of Crops Question 13 Detailed Solution

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Concept:

Duty:

It is the area of land that can be irrigated with a unit volume of water supplied across the base period. It is generally expressed in hectare/cumec.

Delta:

It is the depth of water required to a crop over a unit area across the base period for full growth of the crop. It is generally expressed in cm or m.

Calculation:

Given:

Dicharge (Q) = 3 cumec

Area of land (A) = 5100 hectare

Than, duty = 5100/3 = 1700 hectare/cumec

For delta:

Water depth = 10 cm

Number of watering = 12

Then, delta = 12 x 10 = 120 cm

In an irrigated field, the net irrigation requirement is 15 cm, the application efficiency is 80% and water conveyance efficiency is 60%. What is the gross irrigation requirement (in cm)?

  1. 11.25
  2. 18.75
  3. 25
  4. 31.25

Answer (Detailed Solution Below)

Option 4 : 31.25

Water Requirement of Crops Question 14 Detailed Solution

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Concept:

Gross Irrigation Requirement, GIR = \(\frac{{Net\;Irrigation\;Requirement\left( {NIR} \right)}}{{{\eta _a} \times {\eta _c}\;}}\)

Where ηa and ηc are the application and conveyance efficiency respectively.

Calculation:

Given,

η= 80 %

η= 60 %

NIR = 15 cm

\({\rm{GIR}} = \frac{{15\;cm}}{{0.8 \times 0.6}} = 31.25\;cm\)

The amount of water content remaining in a unit volume of soil after downward gravity drainage has ceased is called:

  1. seepage water
  2. field capacity
  3. readily available moisture
  4. permanent wilting point

Answer (Detailed Solution Below)

Option 2 : field capacity

Water Requirement of Crops Question 15 Detailed Solution

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Concept:

F1 N.M Deepak 18.10.2019 D1


SC = Saturation capacity, FC = Field capacity, OMC = Optimum moisture content, PWP = Permanent welting point and UWP = Ultimate welting point

  • Field capacity is the water that cannot be easily drained under the action of gravity and having its presence in the root zone.
  • The permanent Wilting point is the water content in the root zone below which the roots can no longer extract water for their growth and dries up.
  • Readily available moisture is that portion of available moisture that can be most readily extracted by plants.

  • In general, readily available moisture is approx 75 % of the available moisture.

  • The difference in water content of soil between field capacity and the permanent wilting point is called available moisture.
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