Simple Ratios MCQ Quiz - Objective Question with Answer for Simple Ratios - Download Free PDF
Last updated on Jul 8, 2025
Latest Simple Ratios MCQ Objective Questions
Simple Ratios Question 1:
Which of the following ratios is greatest?
Answer (Detailed Solution Below)
Simple Ratios Question 1 Detailed Solution
Given:
Ratios to compare:
41 : 64, 50 : 59, 40 : 70, 26 : 90
Formula used:
Convert each ratio to decimal:
Calculations:
∴ The greatest ratio is 50 : 59.
Simple Ratios Question 2:
In a bag containing red, green, and pink tokens, the ratio of red to green tokens was 7 : 20, while the ratio of pink to red tokens was 15 : 12. What was the ratio of green to pink tokens?
Answer (Detailed Solution Below)
Simple Ratios Question 2 Detailed Solution
Given:
Ratio of red to green tokens = 7:20
Ratio of pink to red tokens = 15:12
Formula Used:
To find the ratio of green to pink tokens, we align the ratios using the common term "red".
Calculation:
Ratio of red to green tokens = 7:20
Ratio of pink to red tokens = 15:12
First, express the ratios in terms of a common "red" count:
Let red tokens = 84 (LCM of 7 and 12)
Green tokens = (20 × 84) / 7 = 240
Pink tokens = (15 × 84) / 12 = 105
Now, find the ratio of green to pink tokens:
Green : Pink = 240 : 105
Simplify the ratio:
⇒ Green : Pink = (240 / 15) : (105 / 15)
⇒ Green : Pink = 16 : 7
The ratio of green to pink tokens is 16:7.
Simple Ratios Question 3:
Total number of students [boys + girls] in a class is [x + 25]. Number of girls in the class is 2/3rd of the number of boys in the class. Some students participate quiz competition. Ratio of boys who participate and who are not participate is 3:1 and ratio of same for girls is also same. If total 35 students who are not participate then find the value of x?
Answer (Detailed Solution Below)
Simple Ratios Question 3 Detailed Solution
Calculation:
Total students = x + 25
Girls = 2/3 of boys
Let boys = b, then girls = (2/3)b
⇒ Total = b + (2/3)b = (5/3)b
⇒ (5/3)b = x + 25 ⇒ b = (3/5)(x + 25)
Now: Boys (P : NP) = 3:1 ⇒ Non-participating boys = 1/4 of b = b/4
Girls (P : NP) = 3:1 ⇒ Non-participating girls = 1/4 of (2/3)b = (1/6)b
Total non-participating = b/4 + b/6 = (5/12)b
Given: (5/12)b = 35 ⇒ b = (35 × 12)/5 = 84
Total = (5/3) × 84 = 140
x + 25 = 140 ⇒ x = 115
∴ The value of x is 115.
Simple Ratios Question 4:
A : B = 8 : 11, if A = 168, what is the vaule of B.
Answer (Detailed Solution Below)
Simple Ratios Question 4 Detailed Solution
Given:
Ratio of A to B = 8 : 11
A = 168
Calculation:
A / B = 8 / 11
168 / B = 8 / 11
168 × 11 = 8 × B
1848 = 8B
B = 1848 / 8
B = 231
∴ The value of B is: 231
Simple Ratios Question 5:
The ratio of boys and girls in a party is 5 : 3 respectively. If 10 boys leave the party, then the ratio of boys and girls remains 1 : 1. how many people were there in the party?
Answer (Detailed Solution Below)
Simple Ratios Question 5 Detailed Solution
Given:
Ratio of boys to girls = 5:3
After 10 boys leave, ratio becomes = 1:1
Formula used:
Let the number of boys = 5x
Let the number of girls = 3x
Total people = Boys + Girls
After 10 boys leave:
Remaining boys = 5x - 10
Remaining girls = 3x
New ratio = Remaining boys : Remaining girls = 1 : 1
Calculation:
Given new ratio:
(5x - 10) / 3x = 1/1
⇒ 5x - 10 = 3x
⇒ 5x - 3x = 10
⇒ 2x = 10
⇒ x = 5
Total boys = 5x = 5 × 5 = 25
Total girls = 3x = 3 × 5 = 15
Total people = Boys + Girls = 25 + 15 = 40
∴ The correct answer is option (2).
Top Simple Ratios MCQ Objective Questions
If A is 25% less than B, then what will be the value of (2B - A)/A ?
Answer (Detailed Solution Below)
Simple Ratios Question 6 Detailed Solution
Download Solution PDFGiven:
A = 75% of B
Calculation:
A = 3/4 of B
⇒ A/B = 3/4
Let the value of A be 3x and B be 4x
So (2B – A)/A = (2 × 4x – 3x)/3x
⇒ (2B – A)/A = 5x/3x
∴ (2B – A)/A = 5/3
Short Trick:
Ratio of A : B = 3 : 4
∴ (2B – A)/A = (8 – 3) /3 = 5/3
If x : y = 5 : 4, then what will be the ratio of
Answer (Detailed Solution Below)
Simple Ratios Question 7 Detailed Solution
Download Solution PDFGiven:
x : y = 5 : 4
Explanation:
(x/y) = (5/4)
(y/x) = (4/5)
Now,
∴
How much should be added to each term of 4 : 7 so that it becomes 2 : 3?
Answer (Detailed Solution Below)
Simple Ratios Question 8 Detailed Solution
Download Solution PDFGiven :
Ratio of two numbers is 4 : 7
Calculations :
Let the number added to denominator and numerator be 'x'
Now according to the question
(4 + x)/(7 + x) = 2 : 3
⇒ 12 + 3x = 14 + 2x
⇒ x = 2
∴ 2 will be added to make the term in the ratio of 2 : 3.
The ratio of two numbers is 14 : 25. If the difference between them is 264, then which is the smaller of the two numbers?
Answer (Detailed Solution Below)
Simple Ratios Question 9 Detailed Solution
Download Solution PDFGiven:
Ratio of two numbers is 14 : 25
Difference between them is 264
Calculation:
Let the numbers be 14x and 25x
⇒ 25x – 14x = 264
⇒ 11x = 264
∴ x = 24
⇒ Smaller number = 14x = 14 × 24 = 336
∴ The smaller of the two numbers is 336.
The ratio of the salaries of Ravi and Sarita is 3 ∶ 5. If the salary of each is increased by ₹ 5,000, the new ratio becomes 29 ∶ 45. What is the present salary of Sarita?
Answer (Detailed Solution Below)
Simple Ratios Question 10 Detailed Solution
Download Solution PDFGiven:
The ratio of the salaries of Ravi and Sarita is 3 ∶ 5.
If the salary of each is increased by ₹ 5,000, the new ratio becomes 29 ∶ 45.
Formula Used:
Initial salaries: R = 3x and S = 5x.
New salaries: R + 5000 and S + 5000.
New ratio: (R + 5000) / (S + 5000) = 29/45.
Calculation:
Substituting the values of R and S in the new ratio equation:
(3x + 5000) / (5x + 5000) = 29 / 45
Cross multiplying to solve for x:
⇒ 45 × (3x + 5000) = 29 × (5x + 5000)
⇒ 135x + 225000 = 145x + 145000
⇒ 145x - 135x = 225000 - 145000
⇒ 10x = 80000
⇒ x = 8000
Now, finding the current salary of Sarita:
S = 5x = 5 × 8000
S = 40000
The present salary of Sarita is ₹ 40,000.
Shortcut Trick
If x : y = 6 : 5 and z : y = 9 : 25, then what is the ratio of x : z?
Answer (Detailed Solution Below)
Simple Ratios Question 11 Detailed Solution
Download Solution PDFGiven:
x : y = 6 : 5
And z : y = 9 : 25
Calculation :
x/y = 6/5 ---- (i)
And z/y = 9/25
⇒ y/z = 25/9 ---- (ii)
Multiply equation (i) and (ii) we get,
(x/y) × (y/z) = (6/5) × (25/9)
⇒ x/z = 10/3
∴ x : z = 10 : 3
Alternate Method
x : y = 6 : 5 ----- (i)
And z : y = 9 : 25 ---- (ii)
As y is in both the ratios, Multiply (i) × 5 to make equal value of y in both the ratios
x : y = (6 : 5) × 5 = 30 : 25 ---- (iii)
from (ii) and (iii), Since y is same in both the ratios
x : z = 30 : 9 = 10 : 3
In a bag, there are coins of 5ps, 10ps, and 25ps in a ratio of 3 : 2 : 1. If there are Rs. 60 in all, how many 5ps coins are there?
Answer (Detailed Solution Below)
Simple Ratios Question 12 Detailed Solution
Download Solution PDFGiven:
5p : 10p : 25p = 3 : 2 : 1 = 3x : 2x : x
Concept:
1 Rupee = 100 paise
Calculation:
60 Rupees = 60 × 100 = 6000 paise
⇒ 5 × 3x + 10 × 2x + 25 × 1x = 6000
⇒ 15x + 20x + 25x = 6000
⇒ 60x = 6000
⇒ x = 100
∴ Number of 5 paise coins = 3x = 3 × 100 = 300
Speed of Deepak and Vinod are in the ratio of 19 : 12 respectively. If speed of Vinod is 84 km/hr, then what will be the speed of Deepak?
Answer (Detailed Solution Below)
Simple Ratios Question 13 Detailed Solution
Download Solution PDFGiven:
Ratio of Speed of Deepak and Vinod = 19 : 12
Let the speeds of Deepak and Vinod be 19x km/hr and 12x km/hr
Speed of Vinod = 84 km/hr
Calculations:
Speed of Vinod = 84 km/hr
⇒ 12x = 84
⇒ x = 7
Speed of Deepak = 19x = 19 × 7 = 133 km/hr
∴ The speed of Deepak is 133 km/hr.
If P : Q : R = 5 : 3 : 6, then what will be the ratio of P/Q : Q/R : R/P?
Answer (Detailed Solution Below)
Simple Ratios Question 14 Detailed Solution
Download Solution PDFShortcut Trick
P : Q : R = 5 : 3 : 6
Le P be 5x, Q be 3x and R be 6x
Then, (P/Q) ∶ (Q/R) ∶ (R/P) = (5x/3x) ∶ (3x/6x) ∶ (6x/5x)
Let us take the LCM (3, 6, 5) = 30
So, (P/Q) ∶ (Q/R) ∶ (R/P) = (5x/3x) × 30 ∶ (3x/6x) × 30 ∶ (6x/5x) × 30
∴ Required ratio is 50 ∶ 15 ∶ 36
Alternate Method
Given:
P : Q : R = 5 : 3 : 6
Le P be 5x, Q be 3x and R be 6x.
Concept:
If N is divided into a : b, then
First part = N × a/(a + b)
Second part = N × b/(a + b)
Calculations:
The required ratio = P/Q : Q/R : R/P
Multiplying the above ratio with PQR
⇒ Required ratio = P2R : Q2P : R2Q
Putting values of P,Q and R in above ratio, we get
⇒ Required ratio = (5x)2(6x) : (3x)2(5x) : (6x)2(3x)
⇒ Required ratio = (25x2)(6x) : (9x2)(5x): (36x2)(3x)
⇒ Required ratio = (25)(2) : (3)5: (36)
⇒ Required ratio = 50 : 15 : 36
∴ Required ratio is 50 ∶ 15 ∶ 36.
A bag contains Rs. 550 in the form of 50 p, 25 p and 20 p coins in the ratio 2 ∶ 3 ∶ 5. The difference between the amounts that are contributed by the 50 p and the 20 p coins is:
Answer (Detailed Solution Below)
Simple Ratios Question 15 Detailed Solution
Download Solution PDFGiven:
Total Rs. = Rs.550
Calculation:
Let the number of denominations of 50p = 2x
the number of denominations of 25p = 3x
the number of denominations of 20p = 5x
Total paisa = 550 × 100 = 55000 paise
According to the question:
⇒ (50 × 2x) + (25 × 3x) + (20 × 5x) = 55000
⇒ 100x + 75x + 100x = 55000
⇒ 275x = 55000
⇒ x = 55000/275 = 200
Amount in (Rs.) of 50p = 100x = (100 × 200) = 20000 paise = Rs.200
Amount in (Rs.) of 20p = 100x = (100 × 200) = 20000 paise = Rs.200
Required difference = 200 - 200 = 0
∴ The correct answer is 0.