Semiconductors MCQ Quiz - Objective Question with Answer for Semiconductors - Download Free PDF
Last updated on Jun 26, 2025
Latest Semiconductors MCQ Objective Questions
Semiconductors Question 1:
Which parameter of semiconductor diode exhibits positive temperature co-efficient?
Answer (Detailed Solution Below)
Semiconductors Question 1 Detailed Solution
Explanation:
Positive Temperature Coefficient of Semiconductor Diode
Definition: A positive temperature coefficient (PTC) refers to the phenomenon where a parameter increases with an increase in temperature. In the context of semiconductor diodes, certain characteristics exhibit a positive temperature coefficient, which can be crucial for their operation and applications.
Correct Option Analysis:
The correct answer is:
Option 1: Reverse Leakage Current
The reverse leakage current of a semiconductor diode exhibits a positive temperature coefficient. This means that as the temperature increases, the reverse leakage current also increases. This behavior is primarily due to the following reasons:
- Thermal Generation: In a semiconductor, increasing temperature leads to an increase in the thermal generation of charge carriers. This results in a higher concentration of minority carriers, which contributes to a larger reverse leakage current.
- Energy Band Gap Reduction: The energy band gap of a semiconductor narrows as the temperature rises. This reduction facilitates easier carrier movement across the junction, further increasing the reverse leakage current.
- Carrier Mobility: While carrier mobility may decrease with increasing temperature, the dominant factor affecting reverse leakage current is the generation of additional charge carriers, which outweighs the impact of reduced mobility.
Implications:
The positive temperature coefficient of reverse leakage current has several implications:
- Thermal Runaway: In high-power applications, excessive reverse leakage current can lead to thermal runaway, where increasing temperature causes further current increase, potentially damaging the diode.
- Device Reliability: Understanding and mitigating the effects of reverse leakage current are essential for ensuring the reliability and longevity of semiconductor devices.
- Design Considerations: Engineers must account for the temperature-dependent behavior of reverse leakage current when designing circuits involving semiconductor diodes.
Additional Information
To further understand the analysis, let’s evaluate the other options:
Option 2: Reverse Breakdown Voltage
The reverse breakdown voltage of a semiconductor diode generally exhibits a negative temperature coefficient. As temperature increases, the breakdown voltage decreases due to enhanced carrier generation and tunneling effects. This behavior is opposite to what is described by a positive temperature coefficient, making this option incorrect.
Option 3: Forward Voltage
The forward voltage of a semiconductor diode typically decreases with an increase in temperature. This is because higher temperatures reduce the barrier potential of the p-n junction, allowing carriers to move more freely. Hence, the forward voltage exhibits a negative temperature coefficient, not a positive one. Therefore, this option is incorrect.
Option 4: None of the Above
This option is incorrect because, as explained earlier, the reverse leakage current of a semiconductor diode does exhibit a positive temperature coefficient. Selecting "None of the Above" would disregard this established behavior.
Conclusion:
The reverse leakage current of a semiconductor diode is the parameter that exhibits a positive temperature coefficient. This characteristic is crucial for understanding the thermal behavior of diodes and ensuring proper design and application in electronic circuits. Other parameters, such as reverse breakdown voltage and forward voltage, do not exhibit a positive temperature coefficient and instead demonstrate opposite behaviors in response to temperature changes.
Semiconductors Question 2:
An example of type I superconductor is:
Answer (Detailed Solution Below)
Semiconductors Question 2 Detailed Solution
Explanation:
Type I Superconductors
Definition: Type I superconductors are materials that exhibit superconductivity at relatively low critical magnetic fields and transition abruptly from the superconducting state to the normal state. They are characterized by their complete exclusion of magnetic fields (the Meissner effect) and are typically elemental metals.
Working Principle: The phenomenon of superconductivity occurs when a material is cooled below its critical temperature, causing its electrical resistance to drop to zero. Type I superconductors exhibit a single, sharp transition from the superconducting state to the normal state when subjected to a critical magnetic field. They do not allow partial penetration of magnetic fields; instead, they completely expel magnetic fields from their interior.
Characteristics:
- Exhibit the Meissner effect, which is the complete exclusion of magnetic fields from the superconducting material.
- Have relatively low critical magnetic fields compared to Type II superconductors.
- Typically consist of pure, elemental metals rather than alloys or compounds.
Examples: Tin (Sn), lead (Pb), mercury (Hg), and aluminum (Al) are common examples of Type I superconductors.
Correct Option Analysis:
The correct option is:
Option 2: Tin
Tin is a well-established example of a Type I superconductor. It exhibits superconductivity at a critical temperature of approximately 3.72 K and displays the characteristic sharp transition from superconducting to normal state when subjected to its critical magnetic field. Tin’s behavior aligns with the defining properties of Type I superconductors, such as the complete expulsion of magnetic fields and the abrupt transition at the critical field.
Additional Information
To further understand the analysis, let’s evaluate the other options:
Option 1: Niobium tin
Niobium tin (Nb3Sn) is not a Type I superconductor; it is a Type II superconductor. Type II superconductors have higher critical magnetic fields and exhibit partial penetration of magnetic fields, forming vortex states. Niobium tin is widely used in applications requiring high magnetic fields, such as in particle accelerators and MRI machines.
Option 3: Niobium titanium
Niobium titanium (Nb-Ti) is another example of a Type II superconductor. It is an alloy and not a pure elemental metal, which inherently makes it unsuitable as a Type I superconductor. Niobium titanium is commonly used in industrial applications due to its excellent superconducting properties at high magnetic fields.
Option 4: Yttrium barium copper oxide
Yttrium barium copper oxide (YBCO) is a high-temperature superconductor and belongs to the family of Type II superconductors. It is a ceramic compound rather than an elemental metal and exhibits superconductivity at significantly higher critical temperatures compared to Type I superconductors. YBCO is used in various advanced applications, such as in superconducting magnets and power transmission systems.
Conclusion:
Type I superconductors are characterized by their simplicity in composition (typically elemental metals) and abrupt transition between superconducting and normal states. Tin is a classic example of a Type I superconductor, demonstrating the fundamental properties of this category. In contrast, the other options listed in the question pertain to Type II superconductors or high-temperature superconductors, which differ significantly in their behavior and applications. Understanding the distinct features of Type I and Type II superconductors is essential for correctly identifying their examples and applications.
Semiconductors Question 3:
For an insulator, the forbidden energy gap is
Answer (Detailed Solution Below)
Semiconductors Question 3 Detailed Solution
Explanation:
Given:
Energy gap (Eg) for different materials:
Insulator: Eg > 3 eV
Semiconductor: Eg = 0.2 eV to 0.3 eV
Metals: Eg ≈ 0 eV
For an insulator, the energy gap is large, generally greater than 3 eV, which prevents electron transition from the valence band to the conduction band, making electrical conduction nearly impossible.
For semiconductors, the band gap is much smaller (0.2 eV - 0.3 eV), allowing limited conduction under certain conditions. In metals, the band gap is nearly zero, allowing free movement of electrons.
∴ The forbidden energy gap for an insulator is typically around 5 eV.
Semiconductors Question 4:
The Fermi level in an n-type semiconductor at OK lies
Answer (Detailed Solution Below)
Semiconductors Question 4 Detailed Solution
Explanation:
In an n-type semiconductor at 0 K, the Fermi level lies just below the donor level. At absolute zero, electrons in the donor impurity levels are fully occupied and contribute to conduction by moving to the conduction band. Since these donor levels are slightly below the conduction band, the Fermi level is positioned near the donor level, reflecting the highest energy state that electrons can occupy. This placement ensures that most electrons are in the donor levels, and the conduction band remains mostly empty at 0 K, with the Fermi level lying below the donor energy level.
Thus, option '1' is correct.
Semiconductors Question 5:
If a Si wafer with an intrinsic carrier concentration of 1010 cm-3 is doped with 5 × 1015 cm-3 Phosphorus (P) and 1016 cm-3 Boron (B) at room temperature (300 K), then what is the doping in the resultant silicon?
Answer (Detailed Solution Below)
Semiconductors Question 5 Detailed Solution
Explanation:
The intrinsic carrier concentration of silicon (\(n_i\)) is \(10^{10}cm^{-3}\).
Phosphorus (P) is a donor impurity, contributing free electrons, which will make the material n-type.
Boron (B) is an acceptor impurity, contributing holes, which would make the material p-type if it were the only dopant.
Given:
- Phosphorus doping concentration: \(5\times 10^{15}cm^{-3} \)
- Boron doping concentration: \(10^{16}cm^{-3}\).
To determine the resulting type of doping:
- Phosphorus (n-type) adds electrons to the conduction band.
- Boron (p-type) adds holes to the valence band.
We need to compare the concentrations of donors (P) and acceptors (B):
There are more boron atoms \(10^{16}cm^{-3}\) than phosphorus atoms \(5\times 10^{15}cm^{-3} \).
Since the acceptor concentration (Boron) is higher than the donor concentration (Phosphorus), the material will be p-type, dominated by holes from Boron.
Thus, option '3' is correct.
Top Semiconductors MCQ Objective Questions
The number of valence electrons of P and Si are ______ respectively.
Answer (Detailed Solution Below)
Semiconductors Question 6 Detailed Solution
Download Solution PDFMistake Points
The question is asking about the number of valence electrons, and not about the valency of the atom. Since a valence electron is the number of outer shell electrons that is associated with an atom, Phosphorous will have 5, and Silicon will have 4 valence electrons.
The correct answer is 5 and 4.
Explanation:
- A valence electron is an outer shell electron that is associated with an atom.
- These electrons can participate in the formation of a chemical bond.
Key Points
- Silicon has two electrons in its first shell, eight electrons in the second shell, and four (4) electrons in the third shell.
- Since the electrons in the third shell are the outermost electrons, silicon has four valence electrons.
- Phosphorus having an atomic number 15 is a pentavalent element, which means it has 5 valence electrons in its outermost shell.
Semiconductors have ______ conduction band and ______ valence band.
Answer (Detailed Solution Below)
Semiconductors Question 7 Detailed Solution
Download Solution PDFProperty of Semiconductors:
- Semiconductors are the materials that have a conductivity between conductors (generally metals) and non-conductors or insulators (such as ceramics).
- Semiconductors can be compounds such as gallium arsenide or pure elements, such as germanium or silicon.
- Semiconductors have an almost empty conduction band and an almost filled valence band.
- In a semiconductor, the mobility of electrons is higher than that of the holes.
- Its Resistivity lies between 10-5 to 106 Ωm
- Conductivity lies between 105 to 10-6 mho/m
- The temperature coefficient of resistance for semiconductors is Negative.
- The current Flow in the semiconductor is mainly due to both electrons and holes.
Which among the following statements are true with respect to semiconductor breakdown?
Answer (Detailed Solution Below)
Semiconductors Question 8 Detailed Solution
Download Solution PDF- The avalanche breakdown is a phenomenon in which there is an increase in the number of free electrons beyond the rated capacity of the diode; This results in the flow of heavy current through the diode in reverse biased condition
- Avalanche breakdown occurs in lightly doped diode
- Zener breakdown mainly occurs because of a high electric field; When the high electric field is applied across the PN junction diode, then the electrons start flowing across the PN-junction; Consequently, develops little current in the reverse bias
- The Zener breakdown occurs in heavily doped diodes
Important difference between Avalanche and Zener breakdown:
Avalanche Breakdown |
Zener Breakdown |
Lightly doped diode |
Heavily doped diode |
High reverse potential |
Low reverse potential |
Junction is destroyed |
The junction is not destroyed |
A weak electric field is produced |
A strong electric field is produced |
Occurs at high reverse potential |
Occurs at low reverse potential |
Temperature coefficient of resistance in a pure semiconductor is __________.
Answer (Detailed Solution Below)
Semiconductors Question 9 Detailed Solution
Download Solution PDFEffect of temperature on resistance of different material:
Conductor: When the temperature of conducting material increases, the resistance of that particular material increases.
Insulator: When the temperature of conducting material increases, the resistance of that particular material decreases.
Semiconductor: When the temperature of semiconducting material increases, the resistance of that particular material decreases.
A negative coefficient for a material means that its resistance decreases with an increase in temperature. Hence, pure semiconductor materials (silicon and germanium) typically have negative temperature coefficients of resistance.
Match the following:
a) P-N Junction diode |
i) |
b) Zener diode |
ii) |
c) Schottky diode |
iii) |
d) Tunnel diode |
iv) |
Answer (Detailed Solution Below)
Semiconductors Question 10 Detailed Solution
Download Solution PDFConcept:
pn Junction Diode |
Zener Diode |
Schottky Diode |
Tunnel Diode |
Allows current flow only in one direction |
Allows current flow in both directions. |
Allows current flow only in one direction |
Allows current flow in both directions. |
Very Slow Switching Speed |
Low Switching Speed |
High Switching Speed. |
Ultra-High Switching Speed. |
V-I Characteristics do not show a negative resistance region. |
V-I Characteristics do not show a negative resistance region. |
V-I Characteristics do not show a negative resistance region. |
V-I Characteristics shows negative resistance region |
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Valence electrons are the
Answer (Detailed Solution Below)
Semiconductors Question 11 Detailed Solution
Download Solution PDF- The combining capacity of an atom of an element to form a chemical bond is called its valency.
- The outermost electron shell of an atom is called the valence shell.
- The electrons present in the outermost shell of an atom are called valence electrons.
- The valence electron of an atom takes part in a chemical reaction because they have more energy than all the inner electrons.
- The valency of an element is
- Equal to the number of valence electrons
- Equal to the number of electrons required to complete eight electrons in the valence shell.
- Valency of a metal=No. of Valence electrons
- Valency Of a non-metal=8-No. of valence electrons
- For Ex:
- Sodium(Z=11) Electronic Configuration=2,8,1
- Valency=1
- Magnesium(Z=2) Electronic Configuration=2,8,2
- Valency=2
- Chlorine(Z=17) Electronic Configuration=2,8,7
- Valency=8-7=1
- Oxygen= 8 Electronic Configuration=2,6
- Valency=8-6=2
- Sodium(Z=11) Electronic Configuration=2,8,1
The forbidden energy gap for germanium is
Answer (Detailed Solution Below)
Semiconductors Question 12 Detailed Solution
Download Solution PDF
Semiconductor |
Bandgap (0 K) |
Bandgap (300K) |
Si |
1.21 eV |
1.1 eV |
Ge |
0.785 eV |
0.72 eV |
GaAs |
1.52 eV |
1.47 eV |
At room temperature intrinsic carrier concentration is higher in germanium than in silicon because __________.
Answer (Detailed Solution Below)
Semiconductors Question 13 Detailed Solution
Download Solution PDFCarrier concentrations depends on the energy gap in the intrinsic semiconductor.
In the case of Ge and Si the intrinsic carrier concentration of Ge is higher than that of Si because the energy gap in Ge is smaller than that of Si.
The impurity added to extrinsic semiconductors is of the order of
Answer (Detailed Solution Below)
Semiconductors Question 14 Detailed Solution
Download Solution PDFWhat will be the resistance of a semiconductor at a low temperature?