Perceptual Speed Test MCQ Quiz - Objective Question with Answer for Perceptual Speed Test - Download Free PDF
Last updated on Jul 10, 2025
Latest Perceptual Speed Test MCQ Objective Questions
Perceptual Speed Test Question 1:
Comprehension:
Answer (Detailed Solution Below)
Perceptual Speed Test Question 1 Detailed Solution
Perceptual Speed Test Question 2:
Comprehension:
Answer (Detailed Solution Below)
Perceptual Speed Test Question 2 Detailed Solution
Perceptual Speed Test Question 3:
Comprehension:
Answer (Detailed Solution Below)
Perceptual Speed Test Question 3 Detailed Solution
Perceptual Speed Test Question 4:
Comprehension:
Answer (Detailed Solution Below)
Perceptual Speed Test Question 4 Detailed Solution
Perceptual Speed Test Question 5:
Comprehension:
Answer (Detailed Solution Below)
Perceptual Speed Test Question 5 Detailed Solution
Top Perceptual Speed Test MCQ Objective Questions
The difference between the compound Interest and simple interest on a certain sum at 10% per annum for 2 years is ₹631. Determine the sum:
Answer (Detailed Solution Below)
Perceptual Speed Test Question 6 Detailed Solution
Download Solution PDFGiven:
Rate = 10% per annum
Time = 2 years
Difference between CI and SI = Rs 631
Calculation:
For 2 years,
CI - SI = P × (R/100)2
631 = P (10/100)2
631 = P/100
∴ P = 63,100
Alternate Method
Concept Used:
Simple Interest = \(\frac{P× R× T}{100}\)
Compound Interest = P\(\left(1+\frac{r}{100}\right)^t-P\)
Calculation:
⇒ Simple Interest = \(\frac{P× 10× 2}{100}\) = 0.2P
⇒ Compound Interest = P\(\left(1+\frac{10}{100}\right)^2-P\)
⇒ Compound Interest = 1.21P – P = 0.21P
According to the question,
⇒ 0.21P – 0.2P = 631
⇒ 0.01P = 631
⇒ P = \(\frac{631}{0.01}\) = Rs 63,100
Therefore, the sum is Rs 63,100.
DIRECTIONS: A piece of wire 132 cm long is bent successively in the shape of an equilateral triangle, a Square, a circle and a regular hexagon.
The largest area is included when the wire is bent into the shape of a:
Answer (Detailed Solution Below)
Perceptual Speed Test Question 7 Detailed Solution
Download Solution PDFGiven:
The wire is bent into different shapes
Formula Used:
Area of circle = \(\pi r^2\)
Area of Square = a2
Area of equilateral triangle = \(\frac{\sqrt3a^2}{4}\)
Area of regular hexagon = \(\frac{3\sqrt3\times s^2}{2}\)
Calculations:
Length of wire = 132 cm
It is bent into a Square, Circle, Equilateral triangle, and hexagon
First for square
⇒ Perimeter of square = 4a
⇒ 132 = 4a
⇒ a = 33 cm
Area of square = a2 = 33 x 33 = 1089 cm2
Now, For the circle
⇒ The perimeter of the Circle = \(2\pi r\)
⇒ 132 = \(2\times \frac{22}{7} \times r\)
⇒ r = 21 cm
Area of the circle = \(\frac{22}{7}\times 21 \times 21\) = 22 x 3 x 21 = 1386 cm2
Now, For Triangle
⇒ The perimeter of the triangle = 3a
⇒ 132 = 3a
⇒ a = 44 cm
⇒ Area of the triangle = \(\frac{\sqrt3a^2}{4}=\frac{\sqrt3\times22\times22}{4}\) = 209.33 cm2
Now, Last for hexagon
⇒ The perimeter of the hexagon = 6a
⇒ 132 = 6a
⇒ a = 22 cm
Area of the hexagon = \(\frac{3\sqrt3\times a^2}{2}=\frac{3\sqrt3\times 22\times22}{2}\) = 1255.98 cm2
So, The area of the circle is greater than everyone else
∴ Circle has the highest area.
Perceptual Speed Test Question 8:
The difference between the compound Interest and simple interest on a certain sum at 10% per annum for 2 years is ₹631. Determine the sum:
Answer (Detailed Solution Below)
Perceptual Speed Test Question 8 Detailed Solution
Given:
Rate = 10% per annum
Time = 2 years
Difference between CI and SI = Rs 631
Calculation:
For 2 years,
CI - SI = P × (R/100)2
631 = P (10/100)2
631 = P/100
∴ P = 63,100
Alternate Method
Concept Used:
Simple Interest = \(\frac{P× R× T}{100}\)
Compound Interest = P\(\left(1+\frac{r}{100}\right)^t-P\)
Calculation:
⇒ Simple Interest = \(\frac{P× 10× 2}{100}\) = 0.2P
⇒ Compound Interest = P\(\left(1+\frac{10}{100}\right)^2-P\)
⇒ Compound Interest = 1.21P – P = 0.21P
According to the question,
⇒ 0.21P – 0.2P = 631
⇒ 0.01P = 631
⇒ P = \(\frac{631}{0.01}\) = Rs 63,100
Therefore, the sum is Rs 63,100.
Perceptual Speed Test Question 9:
Comprehension:
Answer (Detailed Solution Below)
Perceptual Speed Test Question 9 Detailed Solution
Perceptual Speed Test Question 10:
Comprehension:
In each of the following questions, there are four replicas of one figure on the left side marked with a, b, c and d. But there are five replicas of the same figure on the right side marked with A, B, C, D and E. You are required to select the most similar replica of each of the figures given at the left side from the group of five figures on the right side.
Which figure at the right is most similar to 'a' ?
Answer (Detailed Solution Below)
Perceptual Speed Test Question 10 Detailed Solution
Perceptual Speed Test Question 11:
Comprehension:
Instruction:
This is a test of your ability to match figures quickly and accurately. A figure is given on the left side. On the right side, there are five other figures. You are required to find out which of the five figures is identical to the figure given on the left.
Example:
For the first example, the correct answer is ‘D’. Similarly, correct answers for example 2 and 3 are ‘A’ and ‘D’ respectively.
Give an answer by clicking on the appropriate answer option through the mouse.
(Source: RDSO)
Answer (Detailed Solution Below)
Perceptual Speed Test Question 11 Detailed Solution
Perceptual Speed Test Question 12:
Comprehension:
In each of the following questions, there are four replicas of one figure on the left side marked with a, b, c and d. But there are five replicas of the same figure on the right side marked with A, B, C, D and E. You are required to select the most similar replica of each of the figures given at the left side from the group of five figures on the right side.
Which figure at the right is most similar to 'd' ?
Answer (Detailed Solution Below)
Perceptual Speed Test Question 12 Detailed Solution
Perceptual Speed Test Question 13:
Comprehension:
Instruction:
This is a test of how rapidly and accurately you can see figures in order to match them. Some examples are given below:
Look at the first figure “a” at the left. Which one of the five at the right is most nearly like it? You will find figure D is the one who is similar to ’a’, so answer D has to be clicking the mouse for Example 1.
Look at the second figure “b” at the left. Which figure at the right is the most nearly like it? Figure C is the correct answer, so answer C is to be selected by clicking the mouse.
Now find the figure most nearly matching the third “c” and fourth “d” ones at the left and give correct answer by clicking the mouse.
You should have click B for the third figure ‘c’ and A for the fourth figure 'd'.
Look at the first figure “a” at the left. Which one of the five at the right is most nearly like it?