Clock and Calendar MCQ Quiz - Objective Question with Answer for Clock and Calendar - Download Free PDF

According to the question,

Statement I: Buses for Delhi leave after every 30 minutes, until 11 pm.

Here, no information regarding last bus timing from Noida is given, therefore statement I alone is not sufficient to answer the question.

Statement II: 20 minutes ago, a bus has left for Delhi.

Here, last bus timing is 6:40 pm (7:00 pm - 20 min) for Delhi but frequency of the bus cannot be determined, therefore statement I alone is not sufficient to answer the question.

Combining statement I and II: Buses for Delhi leave after every 30 minutes, until 11 pm. 20 minutes ago, a bus has left for Delhi.

Last bus timing from Noida was 6:40 pm and as buses leave after every 30 minute. Thus the next bus would be at 7:10 pm (6:40 pm + 30 min).

∴ Both statement I and statement II together are needed to answer the question.

Hence, "Option 4" is the correct answer.

According to the question,

Statement I: Buses for Ramnagar leave after every 30 minutes, till 10 p.m.

Here, no information regarding last bus timing from Ramnagar is given, therefore statement I alone is not sufficient to answer the question.

Statement II: Fifteen minutes ago, one bus has left for Ramnagar.

Here, last bus timing is 7:45 pm (8:00 pm - 15 min) for Ramnagar but frequency of the bus cannot be determined, therefore statement I alone is not sufficient to answer the question.

Combining statement I and II: Buses for Ramnagar leave after every 30 minutes, till 10 p.m. Fifteen minutes ago, one bus has left for Ramnagar.

Last bus timing from Ramnagar was 7:45 pm and as buses leave after every 30 minute. Thus the ne×t bus would be at 8:45 pm (6:40 pm + 30 min). It is mentioned that buses leave till 10:00 pm, therefore Hemant can get ne×t bus for Ramnagar from Dhanpur.

∴ Both statement I and statement II together are needed to answer the question.

Hence, "Option 4" is the correct answer.

According to the given question, we need to find the day of the 14th of the given month.

Statement 1: The last day of the month is a Wednesday.

If the last day is Wednesday we are not able to find a day on the 14th of that month because we don't know whether the month is of 28 days or 29 days or 30 days or 31 days.

Therefore, Statement-1 alone is not sufficient to answer the question.

Statement 2: The third Saturday of the month was seventeenth.

If the 17th day of the given month is Saturday then we can easily find the 14th day by subtracting 3 odd days from Saturday i.e., (6 - 3) = 3. means Wednesday.

Therefore, Statement-2 alone is sufficient to answer the question.

Hence, "Option 2" is the correct answer.

Additional InformationHere we use odd days as: Sunday = 0 , Monday = 1, Tuesday = 2, Wednesday = 3, Thursday = 4, Friday = 5, and Saturday = 6.  

From 14th September to 17th October:

Days left in September:

September has 30 days, so days remaining after the 14th = 30 - 14 = 16 days.

Days in October before the 17th:

Days = 17 days.

Total days between the two dates:

Total = 16 (September) + 17 (October) = 33 days.

Calculate the day of the week:

33 days modulo 7 gives us the remainder when divided by 7:

33 ÷ 7 = 5

32 ÷ 7 = 4 remainders 5

Starting from Tuesday (14th September):

Counting 5 days from Tuesday:

Tuesday → Wednesday (1) → Thursday (2) → Friday (3) → Saturday (4) →Sunday(5)

Thus, 17th October will be a Sunday.

Hence the correct answer is, Option(3)

To determine if a particular year is a leap year, we can follow these rules:

1. A year is a leap year if it is divisible by 4.
2. However, if the year is divisible by 100, it is not a leap year, unless:
3. The year is also divisible by 400, in which case it is a leap year.

Now, let's check each option,

1) 1600: It is a leap year because it is divisible by 400.

2) 2000: It is a leap year because it is divisible by 400.

3) 2400: It is a leap year because it is divisible by 400.

Hence, the correct answer is "All options are correct".

Statements:

I. Harish was born on an even date of the month → 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28

II. Harish’s birth date was a prime number → 2, 3, 5, 7, 11, 13, 17, 19, 23, 29

But we know that 2 is the smallest even prime number.

According to both statements we can say that on 2nd February 2000 Harish was born.

Hence, Option (1) is correct.

Logic: If we see carefully we can find that these dates have property  

3rd April, 2005 - 03/04/05  

6th August, 2010 - 06/08/10

5th December, 2013 - 05/12/13

Similarly,

Independence day 2017 - 15 August 2017 - 15/08/17

By above logic:  

No other option satisfy the above condition. So, Indian Independence Day of 2017 has the same property.

Hence, option 1) is the correct answer.

On which date is Evanshu’s birthday.

By using Statement 1:

Evanshu’s birthday is on the Republic Day of a country.

From this we don't know republic day of which country so, we can not find the birth date of Evanshu using statement 2 alone.

By using Statement 2:

The country’s national flag is a tri-colour flag with an Ashoka Chakra in its centre.

So, we can not find the birth date of Evanshu using statement 2 alone.

Thus statement I and II together:

We know that the national flag of India is a tri-colour flag with an Ashoka Chakra in its centre and the Republic Day in India, i.e., on 26th January.

So, we can say that Evanshu's birthday is on 26thJanuary.

Hence, Both statements 1 and 2 are sufficient together​.

Additional InformationThe National Flag of India (Hindi: Tiraṅgā) is a horizontal rectangular tri-colour of India saffron, white and India green; with the Ashoka Chakra, a 24-spoke wheel, in navy blue at its centre.

• Statement I: Sujatha's birthday can be on → Wednesday or Thursday or Friday.

Thus, Statement I alone is not sufficient as no definite answer can be given.

• Statement II: Sujatha's birthday can be on → Tuesday or Wednesday

Thus, Statement II alone is not sufficient as no definite answer can be given.

• Combining data in Statement I and Statement II:

Sujatha's birthday can be on → Wednesday

Thus, both statements are required.

Hence, 'option 4' is the correct answer.

1. Only statement 1 is sufficient but statement 2 is not sufficient. → False

Statement 1: On the 7th day of a month.

From statement 1, we cannot find when is Yuvi's wedding anniversary.

2. Both statement 1 and statement 2 are sufficient independently. → False

As statement 1 is not sufficient independently.

3. ​Only statement 2 is sufficient but statement 1 is not sufficient. → False

Statement 2: The month has 29 days only in a leap year.

Only February has 29 days in a leap year. So, from this statement, it is clear that Yuvi's wedding anniversary is in the month of February, but the date of Yuvi's wedding anniversary cannot be stated from this statement.

So, only statement 2 is not sufficient.

4. Both statement 1 and statement 2 are sufficient together.

Statements:

1: On the 7th day of a month.

2. The month has 29 days only in a leap year.

From 1 we know the date and from 2, we know the month. So, Yuvi's wedding anniversary is on the 7th of February.

Hence, ‘Both statement 1 and statement 2 are sufficient together’ is the correct answer.

Formula Used:

Θ = | Hours × 30^◦ -  × Minute |

Calculation:

Θ = | 2 × 30◦ -  × 13 |

Θ = | 60◦ - |

Θ = | 60◦ - 71.5◦ |

Θ = | - 11.5◦ |

Θ = 11.5◦ 

Hence, "11.5◦"  will be the acute angle between the hour-hand and the minute-hand at 2:13 p.m

According to the given statements,

Statement 1: Arti is six years older than Pranavi.

Statement 2: Pranavi’s sister was born in 1982

Statement 3: Arti’s sister is two years younger than Pranavi’s sister, who is eight years younger than Pranavi

Form statement 3, we can say that Arti’s sister was born in 1984 and Pranavi was born in 1974(from statement 2 Pranavi’s sister is 8 years younger than Pranavi)

From statement 1, Arti is six years older than Pranavi, so Arti was born in 1968

Hence, all the statements are required.

Calculation:   

The angle between two digits = 30° 

⇒ At 2'o clock one hand will be on 12 and second hand will be on 2 So, 30° × 2 = 60° 

∴ At 2'o clock angles between hands will be 60°.

The correct option is 3 i.e. 60° 

Given - 

January 1, 2018 was Monday

Concept used - 

in a normal year number of days = 365

number of odd days = (365/7) = + 1

Solution - 

1 January 2018 = Monday

1 January 2019 = Monday + 1 = Tuesday

∴ January 1, 2019 = Tuesday  

Given: a 12-hour clock when the time is 9 ∶ 25.

Formula used:

where H represents hour and M represents minutes.

Calculation:

Thus, the approximate angle between the minute hand and the hour hand is ' '.