Basic Calculation MCQ Quiz - Objective Question with Answer for Basic Calculation - Download Free PDF

Given:

Side of square field = 79 m

Speed of boy = 4 km/h

Formula used:

Time (t) = Distance / Speed

Calculations:

Perimeter of the square field = 4 × Side

⇒ Perimeter = 4 × 79 = 316 m

Speed in m/s = (4 × 5/18) = 10/9 m/s

Time = Distance / Speed

⇒ Time = 316 / (10/9)

⇒ Time = 284.4 seconds

∴ The correct answer is option (2).

Given:

Initial speed (S₁) = 72 km/h

Time taken (T₁) = 15 hours

Time required (T₂) = 12 hours

Formula used:

S₂ = (S₁ × T₁) / T₂

Where,

S₂ = New speed, S₁ = Initial speed

T₁ = Initial time, T₂ = New time

Calculation:

S₂ = (72 × 15) / 12

⇒ S₂ = 1080 / 12

⇒ S₂ = 90 km/h

∴ The correct answer is option (2).

Given:

Speed of the train = 180 km/hr

Formula Used:

Speed (in m/s) = Speed (in km/hr) × (1000 m / 1 km) × (1 hr / 3600 s)

Calculation:

Speed (in m/s) = 180 km/hr × (1000 m / 1 km) × (1 hr / 3600 s)

Speed (in m/s) = 180 × (1000 / 3600)

Speed (in m/s) = 180 × (5 / 18)

Speed (in m/s) = 50

The correct answer is option 4.

Given:

An object takes 2 seconds to travel once around a circular path with radius 'r'.

Formula used:

Speed (v) = Distance / Time

Calculation:

Circumference of the circle = 2πr

Time taken (t) = 2 seconds

Speed (v) = (2πr) / 2

⇒ v = πr metre/second 

∴ The correct answer is option (4).

Given:

Distance = 45 km = 45 × 1000 = 45000 m

Time = 1 hour 40 minutes = 1 × 3600 + 40 × 60 = 6000 seconds

Formula used:

Speed = Distance ÷ Time

Calculation:

Speed = 45000 ÷ 6000

⇒ Speed = 7.5 m/s

∴ The correct answer is option (3).

Given:

They give us a relation between speed and time.

Formula used:

\(Speed={Distance\over Time}\)

Calculation:

Let the distance of the first person be D and time will be T.

The second person cover the distance = 25% of D = \({25\over100}\times D={D\over4}\)

Time taken by second person = 3T

The speed of the first person = \({D\over T}\)

The speed of the second person = \({{D\over4}\over3T}={D\over12T}\)

The ratio of their speed = \({{D\over T}\over{D\over 12T}}={12\over1}\)

The speed of the first and second person = 12 : 1

∴ The required result will be 12 : 1.

Shortcut Trick  Alternate Method

Given:

The two road is at right angle 

Speed of bus A = 48 km/h

Speed of bus B = 36 km/h

Formula Used:

Speed = Distance / Time

By Pythagoras theorem

Hypotenuse² = Base² + Height²

Calculations:

⇒ Speed of Bus A = 48 km/h = 40/3 m/s

⇒ Speed of bus B = 36 km/h = 10 m/s

Bus A travel distance in 15 sec

⇒ Distance = 40/3 x 15 = 200 m

Bus B travel distance in 15 sec

⇒ Distance = 10 x 15 = 150 m

as the two road is at right angle, so

⇒ Let Height = 200 m

⇒ Base = 150 m

By Pythagoras theorem

Hypotenuse2 = Base2 + Height²

⇒ Distance between two buses = 200² + 150² = 40000 + 22500 = 62500 = 250 m

⇒ Hence, Distance between the two buses is 250 m

Given:-

Speed of first man = 4 km/hr

Speed of second man = 6 km/h

Formula used:- 

Distance = Speed x Time 

Calculation:- 

Distance = 4 ×T

For the second motorist (traveling at 6 km/h)

Distance  = 6 × (T - 0.5) 

Their distances must be the same 

⇒ Distance1 = Distance2 

⇒ 4T = 6(T - 0.5) 

⇒ T = 3/2 Hours

Distance = 4 km/h × (3/2) hours = 6 km

∴ The motorist traveling at 4 km/h traveled a distance of 6 km to reach the destination.  

Given

Two men walk from a place at speeds of 9 km/h and 12 km/h, respectively.

Formula used

Time = distance/speed

Calculation

20 min = 1/3 

Let the total distance be x km.

According to the question

x/9 - x/12 = 1/3

⇒ (4x - 3x)36 = 1/3

⇒ x/36 = 1/3

⇒ x = 12

The distance of the journey is 12 km.

Shortcut TrickThe distance is = [(9 × 12)/(12 - 9)] × 1/3 = 12 km 

Formula Used : 

Speed = Distance/Time

Calculation : 

v = x/t

⇒ Speed = 2.5x/0.75t 

⇒ 25/10 × 100/75 × x/t

⇒ 250/75 × x/t

By putting v = x/t

⇒ 10v/3

∴ The correct answer is 10v/3.

Given:

An aeroplane travels five times as fast as a bus.

Time is taken by bus to cover 60 km = 1 hour 20 minutes(4/3 hour)

Formula used:

Speed = Distance/time

Calculation:

Speed of bus = 60/(4/3)

⇒ 45 km/hr

Speed of aeroplane = 5 × 45

⇒ 225 km/hr

Distance covered in 25 minutes = 225 × 25/60

⇒ 93.75 km

Distance covered in 25 minutes by aeroplane is 93.75 km/hr. 

Given:

The distance between two towns is covered In 7 hours and 30 minutes at the speed of 72 km/h.

Concept used:

Distance = speed × time

Calculation:

Total distance is, 72 × 7.5 = 540 km

New speed is , 72 + 72/4 = 90 km

The required time, 540 / 90 = 6hr

Time saved 7.5 - 6 = 1.5 hr

∴ The correct option is  3

Given:

The distance covered by a train in (5y - 1) hours is (125y3 - 1) km. 

Concept used:

a³ - b³ = (a - b)(a² + ab + b²)

Calculation:

Speed of the train

⇒ (125y3 - 1) ÷ (5y - 1)

⇒ \(\frac {(5y)^3 - 1}{(5y - 1)}\)

⇒ \(\frac {(5y - 1)(25y^2 + 5y + 1)}{(5y - 1)}\)

⇒ (25y2 + 5y + 1) km/h

∴ The speed of the train is (25y2 + 5y + 1) km/h.

Given:

A truck runs 492 km on 36 Litter of diesel.

Calculation:

On 36 Litre of diesel it runs = 492 km.

On 1 Litre of diesel it runs = 492/36 km = 41/3 km

On 33 Litre of diesel it runs = (41/3) × 33 = 451 km

∴ Option 3 is the correct answer.

Given

Distance = 3300

Time = 45 minutes

Formula used

Speed = Distance/Time

Calculation

⇒ 3300 m = 3.3 km

⇒ 45 min = 45/60 = 0.75 hours

Speed = 3.3/0.75 = 4.4 km/hr.

The answer is 4.4 km/hr.