Trigonometric elements MCQ Quiz in বাংলা - Objective Question with Answer for Trigonometric elements - বিনামূল্যে ডাউনলোড করুন [PDF]

Last updated on Apr 13, 2025

পাওয়া Trigonometric elements उत्तरे आणि तपशीलवार उपायांसह एकाधिक निवड प्रश्न (MCQ क्विझ). এই বিনামূল্যে ডাউনলোড করুন Trigonometric elements MCQ কুইজ পিডিএফ এবং আপনার আসন্ন পরীক্ষার জন্য প্রস্তুত করুন যেমন ব্যাঙ্কিং, এসএসসি, রেলওয়ে, ইউপিএসসি, রাজ্য পিএসসি।

Latest Trigonometric elements MCQ Objective Questions

Top Trigonometric elements MCQ Objective Questions

যদি \(\rm m = \left[ \begin{array}{cc} 2 &0\\ 0&1\end{array}\right] and \ n= \left[ \begin{array}{cc} 0 &1\\ -2&0\end{array}\right]\) হয় তাহলে m sinθ + n cosθ এর নির্ণায়কের মান কত?

  1. 1
  2. -1
  3. 3
  4. 2

Answer (Detailed Solution Below)

Option 4 : 2

Trigonometric elements Question 1 Detailed Solution

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গণনা:

m sinθ + n cosθ = sin θ \(\rm \left[ \begin{array}{cc} 2 &0\\ 0&1\end{array}\right]\) + cos θ \(\rm \left[ \begin{array}{cc} 0 &1\\ -2&0\end{array}\right]\)

= \(\rm \left[ \begin{array}{cc} 2\sin θ &0\\ 0&\sin θ\end{array}\right]\) + \(\rm \left[ \begin{array}{cc} 0 &\cosθ\\ -2\cosθ&0\end{array}\right]\)

= \(\rm \left[\begin{array}{cc} 2\sin θ &\cos θ\\ -2\cos θ&\sin θ\end{array}\right]\)

এখন,

|m sinθ + n cosθ| = \(\rm \left| \begin{array}{cc} 2\sin θ &\cos θ\\ -2\cos θ&\sin θ\end{array}\right|\)

= \(2\sin^2\theta \) + \(\rm 2 cos^2\theta \)

= 2( \(\sin ^2 \theta +\cos^2\theta \) )

= 2

সুতরাং, বিকল্প (4) সঠিক।

Trigonometric elements Question 2:

যদি \(\rm m = \left[ \begin{array}{cc} 2 &0\\ 0&1\end{array}\right] and \ n= \left[ \begin{array}{cc} 0 &1\\ -2&0\end{array}\right]\) হয় তাহলে m sinθ + n cosθ এর নির্ণায়কের মান কত?

  1. 1
  2. -1
  3. 3
  4. 2

Answer (Detailed Solution Below)

Option 4 : 2

Trigonometric elements Question 2 Detailed Solution

গণনা:

m sinθ + n cosθ = sin θ \(\rm \left[ \begin{array}{cc} 2 &0\\ 0&1\end{array}\right]\) + cos θ \(\rm \left[ \begin{array}{cc} 0 &1\\ -2&0\end{array}\right]\)

= \(\rm \left[ \begin{array}{cc} 2\sin θ &0\\ 0&\sin θ\end{array}\right]\) + \(\rm \left[ \begin{array}{cc} 0 &\cosθ\\ -2\cosθ&0\end{array}\right]\)

= \(\rm \left[\begin{array}{cc} 2\sin θ &\cos θ\\ -2\cos θ&\sin θ\end{array}\right]\)

এখন,

|m sinθ + n cosθ| = \(\rm \left| \begin{array}{cc} 2\sin θ &\cos θ\\ -2\cos θ&\sin θ\end{array}\right|\)

= \(2\sin^2\theta \) + \(\rm 2 cos^2\theta \)

= 2( \(\sin ^2 \theta +\cos^2\theta \) )

= 2

সুতরাং, বিকল্প (4) সঠিক।

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