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A Hermitian matrix is a special type of square matrix where the matrix is equal to its conjugate transpose. This means if you take the complex conjugate of every element and then swap rows with columns, the matrix stays the same.
Hermitian matrices may have complex numbers, but the elements on the main diagonal are always real numbers (no imaginary part).
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A matrix is a group of numbers or symbols arranged neatly in rows and columns. Each item in the matrix is called an element. The order of a matrix tells us how many rows and columns it has. For example, a 2×2 matrix has 2 rows and 2 columns and contains 4 elements in total.
In this topic, we will learn about Hermitian matrices, their properties, and also study skew-Hermitian matrices along with examples for better understanding.
A Hermitian matrix is a square matrix that stays the same when you take its conjugate transpose. That means if you change each element to its complex conjugate and then switch rows and columns, the matrix does not change.
Hermitian matrices can have complex numbers (numbers that include both real and imaginary parts), but all the numbers on the main diagonal are always real numbers.
A complex number is written in the form a + ib, where:
The name hermitian comes from a French Mathematician Charles Hermite (1822 – 1901). Mathematically, a Hermitian matrix is defined as,
A complex square matrix \( A = [a_{ij}]_{nxn}\) such that \( A^{\ast}=A \), where \( A^{\ast} \) is the conjugate transpose of a matrix A. In other words, if ∀ \( a_{ij}\in A \)
\(a_{ij}=a_{ji}^{\ast}\) where \(a_{ji}^{\ast}\) is the complex conjugate of \(a_{ji}\), then A is a hermitian matrix. Remember that the complex conjugate of a complex number a+ib is obtained by changing the sign of its complex part; a-ib.
For example, \( A=\left[_{6-i\ \ \ \ \ \ -1}^{\ \ 8\ \ \ \ \ \ \ \ 6+i}\right] \)
Then the conjugate of A is, \( \overline{A}=\left[_{6+i\ \ \ \ \ \ -1}^{\ \ 8\ \ \ \ \ \ \ \ 6-i}\right] \)
and the transpose conjugate of A is, \( A^{\ast}=\left[_{6-i\ \ \ \ \ \ -1}^{\ \ 8\ \ \ \ \ \ \ \ 6+i}\right] \)
As, \( A^{\ast}=A \),
Therefore A is a hermitian matrix.
Some properties of a hermitian matrix are given below:
To better understand Hermitian matrices, it helps to first know a few related terms:
A square matrix is called a skew-hermitian matrix if its conjugate transpose is the negative of the original matrix i.e. \( A^{\ast}=-A \). In other words, if ∀ \( a_{ij}\in A \)
\(a_{ij}=-a_{ji}^{\ast}\) where \(a_{ji}^{\ast}\) is the complex conjugate of \(a_{ji}\), then A is a skew-hermitian matrix.
For example, \( A=\begin{bmatrix}\ \ \ \ \ 0&\ 1+2i&\ \ 3+i\\
-1+2i&\ \ \ \ 3i&\ \ 4+3i\\
-3+i&-4+3i&\ \ \ -2i\end{bmatrix} \)
So, conjugate of A is, \( \overline{A}=\begin{bmatrix}\ \ \ \ \ 0&\ 1-2i&\ \ 3-i\\
-1-2i&\ \ \ \ -3i&\ \ 4-3i\\
-3-i&-4-3i&\ \ \ 2i\end{bmatrix} \)
Now, conjugate transpose of A is, \( A^{\ast}=\begin{bmatrix}\ \ \ \ 0&-1-2i&\ \ -3-i\\
1-2i&\ \ \ \ -3i&\ \ -4-3i\\
3-i&\ \ 4-3i&\ \ \ \ \ \ \ \ 2i\end{bmatrix} \)
As we get, \( A^{\ast}=-A \), therefore the given matrix A is a skew-hermitian matrix.
Any square matrix can be uniquely represented as a sum of a hermitian and a skew-hermitian matrix.
Let us take a matrix, A then
\( A=\frac{1}{2}\left(A+A^{\ast }\right)+\frac{1}{2}\left(A-A^{\ast }\right) \) , where \( \left(A+A^{\ast}\right) \) is hermitian and \(\left(A-A^{\ast }\right) \) is skew-hermitian.
Some properties of a skew-hermitian matrix are given below:
Eigenvalues of a Hermitian matrix are always real.
Let us consider A to be a hermitian matrix, such that \( A^{\ast}=A \) and \( \lambda \) be the eigenvalue of A, where \( \lambda\ne0 \), such that
\( A\vec{v}=λ\vec{v} \), where \( \vec{v} \) is a non-zero vector.
\( \Rightarrow\left(A\vec{v}\right)^{\ast}=\left(λ\vec{v}\right)^{\ast} \)
\( \Rightarrow\left(\vec{v}^{\ast}A^{\ast}\right)=\left(λ^{\ast}\vec{v}^{ \ast}\right) \)
Multiplying both sides by \( \Rightarrow\vec{v} \), using matrix multiplication we get
\( \Rightarrow\left(\vec{v}^{\ast}A^{\ast}\vec{v}\right)=\left(λ^{\ast}\vec{v}^{\ast}\vec{v}\right) \)
As A is a hermitian matrix so we know that, \( A^{\ast}=A \)
\( \Rightarrow\left(\vec{v}^{\ast}A\vec{v}\right)=\left(λ^{\ast}\vec{v}^{\ast}\vec{v}\right) \)
\( \Rightarrow\left(\vec{v}^{\ast}\lambda\vec{v}\right)=\left(λ^{\ast}\vec{v}^{\ast}\vec{v}\right) \)
\( \Rightarrow\left(\lambda\vec{v}^{\ast}\vec{v}\right)=\left(λ^{\ast}\vec{v}^{\ast}\vec{v}\right) \)
Since \( \vec{v} \) is non-zero, so we can say, \( \vec{v}^{\ast}\vec{v}\ne0 \).
\( \Rightarrow \lambda =\lambda ^{\ast } \)
\( \Rightarrow\lambda\in R \)
Thus the eigenvalues of a hermitian matrix are always real.
Example of Eigenvalues of a Hermitian Matrix: Let us consider, \( A=\left[_{1+i\ \ \ \ \ \ 2}^{\ \ 3\ \ \ \ \ \ \ \ 1-i}\right] \)
This is a hermitian matrix, as \( A^{\ast}=A \)
The characteristic polynomial of A is,
\( \left|A-\lambda I\right|=\left|_{1+i\ \ \ \ \ \ 2-\lambda}^{3-\lambda\ \ \ \ \ 1-i}\right| \)
\( =\left(3-\lambda\right)\left(2-\lambda\right)-\left[\left(1-i\right)\left(1+i\right)\right] \)
\( =\lambda^2-5\lambda+4 \)
\( =\left(\lambda-1\right)\left(\lambda-4\right) \)
Thus, the eigenvalues of A are 1 and 4 which are real.
Some solved examples on Hermitian Matrix are given below:
Example 1: Check whether the given matrix is hermitian or not. \( \begin{bmatrix}\ \ \ 1&1+i&\ 4-5i\\ 1-i&\ \ \ 3&\ \ \ 3i\\ 4+5i&-3i&\ -2\end{bmatrix} \)
Solution: Let the given matrix be A.
To check whether the given matrix is hermitian or not, first we have to find the conjugate transpose.
Therefore, conjugate of the given matrix, \( \overline{A\ }=\begin{bmatrix}\ \ \ 1&1-i&\ 4+5i\\
1+i&\ \ \ 3&\ \ -3i\\
4-5i&\ \ 3i&\ \ -2\end{bmatrix} \)
Now we have to transpose it, so conjugate transpose of A is \( A^{\ast}=\begin{bmatrix}\ \ \ 1&\ 1+i&\ 4-5i\\
1-i&\ \ \ \ 3&\ \ \ \ 3i\\
4+5i&\ -3i&\ \ -2\end{bmatrix} \)
Thus we see that the given matrix satisfies the condition \( A^{\ast}=A \) , hence the given matrix is a hermitian matrix.
Example 2: Check whether the matrix
A =
[ 6 − 7i 0 ]
[−99 6 + 7i ]
is a Hermitian matrix.
Solution:
To check if the matrix is Hermitian, we need to find the conjugate transpose of A and compare it with A.
Step 1: Take the complex conjugate of each element in A
Conjugate of A =
[ 6 + 7i 0 ]
[−99 6 − 7i ]
Step 2: Take the transpose of the conjugate (interchange rows and columns):
Conjugate transpose A* =
[ 6 + 7i −99 ]
[ 0 6 − 7i ]
Step 3: Compare A with the original matrix A*
Original A =
[ 6 − 7i 0 ]
[−99 6 + 7i ]
Since A* is not equal to A, the matrix is not Hermitian.
The given matrix is not a Hermitian matrix.
Example 3: Check whether the matrix
A =
[ 2 3 + i ]
[ 3 − i 5 ]
is a Hermitian matrix.
Solution:
To check if A is Hermitian, we find the conjugate transpose of A and compare it with A.
Step 1: Take the complex conjugate of each element in A
Conjugate of A =
[ 2 3 − i ]
[ 3 + i 5 ]
Step 2: Take the transpose of the conjugate (swap rows and columns):
Conjugate transpose A* =
[ 2 3 + i ]
[ 3 − i 5 ]
Step 3: Compare A with the original matrix A*
Original A =
[ 2 3 + i ]
[ 3 − i 5 ]
Since A* is equal to A, the matrix is Hermitian.
The given matrix is a Hermitian matrix.
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