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In mathematics and geometry, a cross-section is the shape created when an object is sliced by a plane. If the formation and dimension of the cross-section are the same at every point throughout the length/ breadth/ height of the solid then the cross-section will always be uniform.
Instance like when a tree is cut it shows a ring shape throughout the surface. This is a real-life example of cross-sections. With this article, you will learn the cross section’s meaning, its type and cross sectional area of geometric figures with examples.
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In geometry, a cross-section is the shape you get when you cut a 3D solid with a flat surface or plane. It shows a 2D shape formed by the slice, usually made parallel to the base of the solid.
For example, If you cut a sphere in any way, the cross-section will always be a circle.
If you cut a cone straight down (vertically), the shape you get is a triangle. If you cut it flat across (horizontally), the shape is a circle.
If you cut a cylinder straight down (vertically), the shape is a rectangle. If you cut it flat across (horizontally), the shape is a circle.
The cross-section in general symbolizes the intersection of a plane with a three-dimensional object or shape. In the previous header we read that depending on the orientation of the plane, we can receive several cross-sections from the identical entity or object. The three common types of orientations are;
Learn the different Properties of Rectangles.
In a vertical or perpendicular cross section, the given plane cuts the solid shape in the vertical orientation i.e., perpendicular to the base of the solid shape, in such a way that it constructs a perpendicular cross-section.
OR
When an object is sliced by the plane perpendicular to the base of the object, that is, at an angle of 90 degrees we get a vertical cross-section of the object.
For example, if we consider a cylindrical bar. The vertical or perpendicular cross section of the cylindrical bar will be a rectangle.
In a horizontal or parallel cross section, the given plane cuts the solid shape in the horizontal orientation i.e., parallel to the base of the solid shape, in such a way that it constructs a parallel cross-section.
OR
When an object is sliced by the plane parallel to the base of the object, that is, at an angle of 0 degrees we get a horizontal cross-section of the object.
For example, if we consider a cylindrical bar. The horizontal or parallel cross section of the cylindrical bar will be a circle.
Other than vertical and horizontal when the cross-section is created and the plane intersects or crosses the object at an angle that is greater than 0 degrees and less than 90 degrees; such a cross section is called an inclined cross section.
Now that we know the cross-section definition as well as its different types, let us understand the concepts of the cross sectional area of different geometric shapes.
A cone is a type of pyramid but with a circular cross-section or it is a pyramid-like structure having a circular base and a triangular top. Relying upon the position of the plane which encounters the cone and the angle of intersection, different types of conic sections are formed namely; circle, ellipse, parabola and hyperbola.
Read more about the Mensuration 2D here.
Consider the figure below to understand the various cross section of a cone.
Check out this article on Parabola Ellipse and Hyperbola.
A cube is a three-dimensional figure having six faces and each of the faces links with the other four faces. Also, all the sides of a cube are of equal length. Let us understand the various cross sections of a cube.
The figure below shows the various cross sections of a cube.
Learn about the surface area of a cube here.
A cuboid is a 3D shape. In a cuboid, the sides are of distinct lengths and are named length, breadth, and height. Let us understand the various cross sections of a cuboid.
Consider the below diagram to understand the same.
Know more about the Mensuration 3D.
A cylinder is a 3D tube-like structure including two parallel circular bases bound by a curved surface at a particular length from the center.
As per the cutting line cut, the cross-section of a cylinder can be a circle, a rectangle, or an oval. Let us understand them one by one.
The below represents all the cross sections so formed in a cylinder.
A sphere represents a perfectly round 3D formation such that every point on its surface is at an equal distance from its centre. We can be considered our earth as an example of the same. Also, it has the smallest surface area for its volume.
Let us understand the cross-section of a sphere. Any cross-section of a sphere will always be a circle irrespective of the orientation of the plane. The figure below shows the same.
In the previous section, we read about the various cross sections formed by the different figures as per the orientation of the cutting line. Moving ahead, learn about the cross sectional area formula for different shapes.
When a plane crosses a solid object, an area is projected onto the given plane. Its projection is called the cross-sectional area. Depending on the figure and formation of the cross section, we can calculate the area by recognizing its dimensions.
Consider the case of a cube. When the cutting plane is parallel to the bases of the cube or any side of the cube the cross-section obtained will be a square.
Thus the area of a square= \(a^{2}\)
In the case of a cone; when the cutting front is parallel to the base of the cone a circle is obtained. Thus the cross sectional area of a circle= \(\pi r^{2}\).
Next, consider the case of a cylinder, wherein the cutting plane slices the cylinder such that it is perpendicular to the bases, the cross-section received will be a rectangle.
The cross sectional area of a rectangle=length × breadth.
Learn the concepts of Three Dimensional Geometry here.
A cross section is always a two-dimensional shape formed by slicing a three-dimensional object. Its shape depends on how and where the object is cut. For symmetrical solids, cross sections taken parallel to the base have the same shape and size as the base.
Cross sections are used in various fields like engineering, architecture, medicine, and science to study the inner structure of objects. They help in understanding shapes, measuring areas, and designing strong, efficient structures or parts by showing internal details of 3D objects in 2D form.
Now that we know what is the cross sectional area? how to find the same with detailed images. Let us go through some solved examples related to the topic for more practice.
Solved Example 1: Determine the cross-sectional area of a cylinder whose height is 20cm and diameter is 6cm. Given that the plane that cuts the cylinder is parallel to one of its bases.
Solution: Given;
Height of the cylinder =20cm
Diameter of the cylinder = 6cm
Radius=3 cm
The plane when cutting the cylinder that is parallel to any of its bases will give a circle.
Thus, the area of the circle is\( πr^{2}\), where r is the circle’s radius.
Substituting the values we get;
Area of circle =\( \pi\times3\times3=\frac{22}{7}\times3\times3=28.285\text{ cm}^2\) .
Also, learn about the Circumference of a Circle.
Example 2: Obtain the cross-sectional area of a plane parallel to the base of a cube. Given the volume of the cube is equal to 64 \(cm^{3}\).
Solution: Here we need to find the cross-sectional area of the cube as the plane is parallel to the base. Thus the first obtain the measure of the side.
The volume of a cube is calculated using the formula; \(side^{3}\)
Given that;
\(side^{3} = 64\)
Thus each side =4 cm
In our case, the cross-section of the cube will be a square, as the plane is parallel to the base of the cube.
The length of the side of a square=4 cm
The area of a square= \(side^{2}\) = \(4^{2}\) sq.cm=16 sq.cm.
Solved Example 3: Determine the cross sectional area of a cone whose height is 22cm and radius is 5cm. Given that the cutting face is parallel to the base of the cone.
Solution: Given;
Height of the cone=22cm
Radius of the cone = 5cm
When the cutting face is parallel to the base of the cone a circle is obtained.
Thus, the area of the circle is\( πr^{2}\), where r is the circle’s radius.
Substituting the values we get;
Area of circle =\( \pi\times5\times5=\frac{22}{7}\times5\times5=78.571\text{ cm}^2\).
We hope that the above article is helpful for your understanding and exam preparations. Stay tuned to the Testbook App for more updates on related topics from Mathematics, and various such subjects. Also, reach out to the test series available to examine your knowledge regarding several exams.
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