Question
Download Solution PDFWhat shall be the radius of an exit taxiway with design exit speed of 90 kmph and coefficient of friction 0.13?
This question was previously asked in
ESE Civil 2015 Paper 2: Official Paper
Answer (Detailed Solution Below)
Option 2 : 500 m
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ST 1: UPSC ESE (IES) Civil - Building Materials
20 Qs.
40 Marks
24 Mins
Detailed Solution
Download Solution PDFConcept:
The radius of exit taxiway is given by,
Where,
V = Design exit speed
f = Coefficient of friction
Calculation:
⇒ R = 498.46 ≈ 500 m
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