What is the reactive power of a 3-phase, delta-connected system with line voltage of 100 V and line current of 40 A if the phase difference between the voltage and the current is 36.87°?

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SSC JE Electrical 05 Jun 2024 Shift 3 Official Paper - 1
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  1. 4.155 KVAR
  2. 6.155 KVAR
  3. 2.155 KVAR
  4. 8.155 KVAR

Answer (Detailed Solution Below)

Option 1 : 4.155 KVAR
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Detailed Solution

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Concept of Reactive Power:

In a three-phase system, reactive power (Q) can be calculated using the formula:

Q = √3 × Vline × Iline × sin(ϕ)

Where,

  • Vline = Line Voltage
  • Iline = Line Current
  • ϕ = Phase difference between the voltage and the current
     

Given Data:

  • Line Voltage (Vline) = 100 V
  • Line Current (Iline) = 40 A
  • Phase Difference (ϕ) = 36.87°

Calculation:

Using the formula:

Q = √3 × Vline × Iline × sin(ϕ)

We have,

sin(36.87°) = 0.6

Therefore,

Q = √3 × 100 V × 40 A × 0.6

⇒ Q = 1.732 × 100 × 40 × 0.6

⇒ Q = 4156.8 VAR

Conclusion:

  • Hence, the reactive power of the 3-phase, delta-connected system is 4156.8 VAR = 4.155 KVAR
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