Question
Download Solution PDFWhat is the current flowing through a 10 kΩ, 1 W resistor?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept
The power across a resistor is given by:
\(P={V^2\over R}=I^2R=VI\)
where, P = Power
V = Voltage
R = Resistance
I = Current
Calculation
Given, I = 1 W
R = 10 kΩ
\(P=I^2R\)
\(1=I^2\times 10\times 10^3\)
I = 0.01 A
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