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The value of k for which the function 

is probability density function, is

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SSC CGL Tier-II ( JSO ) 2016 Official Paper ( Held On : 2 Dec 2016 )
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Answer (Detailed Solution Below)

Option 3 : 3
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Detailed Solution

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Given

f(x) = { ke-3x, x > o

          { 0, elsewhere

Concept used

 =  +  = 1

Calculation

According to given part

⇒ = 0

⇒ 0 +  = 0

⇒ ∫ke-3xdx = 1

⇒ k[-e-3x/3]

⇒ -k/3[e-∞- e0] = 1

⇒ -k/3(0 – 1) = 1

⇒ k./3 = 1

∴ The value of k = 3 for PDF

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