Question
Download Solution PDFThe three important oxidation states of Phosphorus are:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
- Phosphorus is a group 15 or group V A element.
- It has outer electronic configuration ns2np3.
- Phosphorus unlike Nitrogen exists in many forms such as red phosphorus, white phosphorus, etc, each of them having a different lattice structure.
- Phosphorus mainly exists as P4, and is a tetrahedral molecule where each Phosphorus atom is linked to another P atom via single covalent bonds.
- This makes Phosphorus to be much more reactive than Nitrogen as single bonds are much easier to break.
- The breaking of the P-P bond requires much less energy.
- This makes Phosphorus quite reactive in nature.
Explanation:
- The element P has five electrons in the outermost shell and is short of three electrons to complete its octet.
- One case may be such that P can accept three electrons from other elements and be anion P3-, which is not easy considering the energy of electron gain enthalpy.
- So, they make mostly covalent compounds by sharing three electrons in most cases and P3- is formed in very rare cases.
- As Phosphorus has a vacant 3d orbital, which can accept electrons in it, it can expand its octet and sometimes exhibits a covalency of 5 in compounds such as PCl5.
- In PCl5, the oxidation state of P is +5, in that case, all 5 valence electrons take part in bonding.
- In PCl3, the oxidation state of P is +3.
- In P2O5 also, the oxidation state of P is +5.
- Phosphorus shows the oxidation state of -3 in compounds such as phosphine, PH3.
Hence, the three important oxidation states of Phosphorus are -3, +3 and +5.
Last updated on Jun 17, 2025
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