The period of oscillation of a magnet in a vibration magnetometer is 2 sec. The period of oscillation of a magnet whose magnetic moment is four times that of the first magnet is

CONCEPT:

Vibration Magnetometer

• A vibration magnetometer measures the period of oscillation of a magnet in a magnetic field.
• The period of oscillation (T) is inversely proportional to the square root of the magnetic moment (M) of the magnet.
• Mathematically, $T \propto \frac{1}{\sqrt{M}}$ .

EXPLANATION:

• Given:
  • The period of oscillation of the first magnet, $T_1 = 2$ sec.
  • The magnetic moment of the second magnet, $M_2 = 4M_1$ .
• Since $T \propto \frac{1}{\sqrt{M}}$ :
  • $T_2 = \frac{T_1}{\sqrt{4}} = \frac{2}{2} = 1$ sec.

Therefore, the correct answer is option 1: 1 sec.