Question
Download Solution PDFThe maximum efficiency of a half-wave rectifier is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept
The efficiency of the rectifier is defined as the ratio of the DC output power to the AC output power.
For half-wave rectifier
The DC output power is given by:
The AC output power is given by:
The efficiency is given by:
η = 40.6%
For full-wave rectifier
The DC output power is given by:
\(P_{o(avg)}=V_{o(avg)}I_{o(avg)}\)
The AC output power is given by:
The efficiency is given by:
η = 81.2%
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