Question
Download Solution PDFThe H.C.F of \(\frac{1}{2},\frac{2}{3}, \frac{3}{4}, \frac{4}{5}\) is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
The H.C.F of \(\dfrac{1}{2}\), \(\dfrac{2}{3}\), \(\dfrac{3}{4}\), \(\dfrac{4}{5}\) is
Formula used:
H.C.F of fractions = \(\dfrac{H.C.F\ of\ numerators}{L.C.M\ of\ denominators}\)
Calculation:
Numerators: 1, 2, 3, 4
Denominators: 2, 3, 4, 5
H.C.F of numerators = 1
L.C.M of denominators = 60
⇒ H.C.F of fractions = \(\dfrac{1}{60}\)
∴ The correct answer is option (4).
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