The equation of a wave on a string of linear mass density 0.04 kgm−1 is given by

The tension in the string is

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VITEEE PYP_125Qs150Min125Marks
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  1. 4.0N
  2. 12.5N
  3. 0.5N
  4. 6.25N

Answer (Detailed Solution Below)

Option 4 : 6.25N
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JEE Main 2025 (Session II) All India Live Test
75 Qs. 300 Marks 180 Mins

Detailed Solution

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Concept:

Wave Equation and Tension in a String:

  • The wave equation for a string is given by: y = A sin( 2π ( t / T - x / λ ) )
  • Where:
    • A = Amplitude of the wave
    • T = Period of the wave
    • λ = Wavelength of the wave
    • t = Time
    • x = Position along the string
  • For a string under tension, the tension (T) is related to the wave speed and linear mass density (μ) by the formula: T = μ v² = μ ( ω / k )²
  • Where:
    • μ = Linear mass density (kg/m)
    • v = Wave speed (m/s)
    • ω = Angular frequency (rad/s)
    • k = Wave number (rad/m)

 

Calculation:

Given,

Amplitude, A = 0.02 m

Linear mass density, μ = 0.04 kg/m

The wave number (k) is given by: k = 2π / λ = 2π / 0.50 = 2π / 0.50 rad/m

The angular frequency (ω) is given by: ω = 2π / T = 2π / 0.004 rad/s

The tension in the string is:

T = μ ( ω / k )² = 0.04 × ( (2π / 0.004) / (2π / 0.50) )² = 6.25 N

∴ The tension in the string is 6.25 N.

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