Question
Download Solution PDFThe base of a right pyramid is a square of side
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
The base of a right pyramid is a square of side
Slant edge length = 10 cm
Formula Used:
Volume of pyramid = (area of base × height)/3
Calculation:
Let OABCD is a right pyramid of square base
Let [OP = h] be the height of the pyramid
To find the height OP at first we have to find DP
DP = Half of the diagonal of square
⇒ DP = (1/2) × [√2 × 8√2] = 8 cm
Now, In right angled triangle OPD
OP2 = OD2 - DP2 [∠OPD = 90°]
⇒ OP2 = 102 - 82 = 62
⇒ OP = 6
⇒ Height of the pyramid = 6 cm
Now, Volume of the pyramid = (1/3) × area of base × 6
⇒ (1/3) × (8√2)2 × 6
⇒ 256 cm3
∴ The volume of the pyramid is 256 cm3.
Last updated on Jul 7, 2025
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