Question
Download Solution PDFసమీకరణం యొక్క గ్రాఫ్ x – 7y = -42 అనేది P(α, β) వద్ద y-అక్షాన్ని ఖండిస్తుంది మరియు 6x + y – 15 = 0 యొక్క గ్రాఫ్, అనేది Q(γ, δ) వద్ద x-అక్షాన్ని ఖండిస్తుంది. అయితే α + β + γ + δ విలువ కనుగొనండి?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDF⇒ సమీకరణం x – 7y = (-42) అనేది y-అక్షాన్ని P(α, β) వద్ద ఖండిస్తే, అప్పుడు x = 0,
⇒ 0 – 7y = (-42)
⇒ y = 42/7 = 6
⇒ α = 0 మరియు β = 6
సమీకరణం 6x + y – 15 = 0 అయితే, Q(γ, δ) వద్ద x-అక్షాన్ని ఖండిస్తే, అప్పుడు y = 0.
⇒ 6x + 0 = 15
⇒ x = 15/6 = 5/2
⇒ γ = 5/2 మరియు δ = 0
ఇప్పుడు, (α + β + γ + δ)
⇒ 0 + 6 + 5/2 + 0
⇒ 17/2
Last updated on Jul 23, 2025
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