Select the set in which the numbers are related in the same way as are the numbers of the following sets.

(NOTE : Operations should be performed on the whole numbers, without breaking down the numbers into its constituent digits. E.g. 13 - Operations on 13 such as adding /subtracting/multiplying etc. to 13 can be performed. Breaking down 13 into 1 and 3 and then performing mathematical operations on 1 and 3 is NOT allowed)

(4, 6, 9)

(25, 10, 4)

Question

Question

This question was previously asked in

SSC CGL 2022 Tier-I Official Paper (Held On : 13 Dec 2022 Shift 4)

Answer 1

The logic followed here is : (Square root of 1st number) × (Square root of 3rd number) = 2nd number

Given :

\( \sqrt{4}\) × \(\sqrt{9}\) = 6

2 × 3 = 6

6 = 6 (LHS = RHS)

\(\sqrt{25}\) × \(\sqrt{4}\) = 10

5 × 2 = 10

10 = 10 (LHS = RHS)

So,

\( \sqrt{23} \) × \(\sqrt{32} \) = 3

4.49 × 5.65 = 3

25 ≠ 3 (LHS ≠ RHS)

\( \sqrt{45} \) × \(\sqrt{19}\) = 20

6.7 × 4.35 = 20

29 ≠ 20 (LHS ≠ RHS)

\(\sqrt{6}\) × \(\sqrt{216}\) = 36

\(\sqrt{6}\) × \(6\sqrt{6}\) = 36

36 = 36 (LHS = RHS)

\(\sqrt{98}\) × \(\sqrt{89}\) = 7

9.89 × 9.43 = 7

93 ≠ 7 (LHS ≠ RHS)

Hence, "Option - (3)" is the correct answer.