ट्रान्झिस्टरचे बीटा विद्युतप्रवाह गुणोत्तर किती आहे?

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RRB ALP CBT 2 Electronic Mechanic Previous Paper: Held on 23 Jan 2019 Shift 1
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  1. IC/IB
  2. IB/IE 
  3. IE/IC 
  4. IC/IE

Answer (Detailed Solution Below)

Option 1 : IC/IB
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सामान्य-उत्सर्जक विद्युतप्रवाह लाभ (β) म्हणजे ट्रान्झिस्टरच्या संग्राहक विद्युतप्रवाहाचे ट्रान्झिस्टरच्या पायाभूत विद्युतप्रवाहाशी असलेले गुणोत्तर, म्हणजे,

\(β = \frac{{{I_C}}}{{{I_B}}}\)

26 June 1

आणि समान पायाभूत DC विद्युतप्रवाह (α) हे ट्रान्झिस्टरच्या संग्राहक प्रवाहाचे ट्रान्झिस्टरच्या उत्सर्जक प्रवाहाशी गुणोत्तर आहे, उदा.

\(α = \frac{{{I_C}}}{{{I_E}}}\)

ट्रान्झिस्टर विद्युतप्रवाह खालील संबंधाने संबंधित आहेत:

IE = IB + IC

α आता असे लिहिले जाऊ शकते:

\(α = \frac{{{I_C}}}{{{I_B+I_C}}}\)

Iद्वारे अंश आणि विभाजक या दोन्हींना विभाजित करून, आपल्याला मिळते:

 

\(α = \frac{{{I_C/I_B}}}{{{1+I_C/I_B}}}\)

कारण \(β = \frac{{{I_C}}}{{{I_B}}}\)

\(α = \frac{β }{{β + 1}}\) 'किंवा'

\(β = \frac{α }{{1-α}}\)

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