Question
Download Solution PDFएका समकोन शंकूचा पाया
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेले आहे:
एका समकोन शंकूचा पाया
तिरकस किनार = 10 सेमी
वापरलेले सूत्र:
शंकूचे घनफळ = (पायाचे क्षेत्रफळ × ऊंची)/3
गणना:
समजा, OABCD चौरसाकृती पाया असलेला एक समकोन शंकू आहे.
समजा, [OP = h] ही शंकूची ऊंची आहे.
OP ची ऊंची माहीत मारण्यासाठी आपल्याला प्रथम DP चे मूल्य माहीत करावे लागेल.
DP = (1/2) × चौरसाच्या कर्ण
⇒ DP = (1/2) × [√2 × 8√2] = 8 सेमी
आता, काटकोन त्रिकोण OPD मध्ये
OP2 = OD2 - DP2 [∠OPD = 90°]
⇒ OP2 = 102 - 82 = 62
⇒ OP = 6 सेमी
⇒ शंकूची ऊंची = 6 सेमी
आता, शंकूचे घनफळ = (1/3) × पायाचे क्षेत्रफळ × 6
⇒ (1/3) × (8√2)2 × 6
⇒ 256 सेमी3
∴ शंकूचे घनफळ = 256 सेमी3.
Last updated on Jul 19, 2025
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