Question
Download Solution PDFएखादी वस्तू x = 0 मीटर आणि t = 0 सेकंदामध्ये विराम अवस्थेत सुरू होते. ती x – अक्षाच्या बाजूने 2 मी/से2 या स्थिर त्सवरणासह गतिमान आहे. 1 सेकंद आणि 5 सेकंद या वेळेदरम्यान तिचा सरासरी वेग किती आहे?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
- सरासरी वेग = एकूण विस्थापन/ एकूण वेळ कालावधी
- गतीचे समीकरण:
- v = u + at
- v 2 = u 2 + 2as
- s = ut + 1/2 at 2
गणना:
दिलेल्याप्रमाणे:
वेळ मध्यांतर = 5 s & 1 s, प्रारंभिक वेग u = 0, आणि, प्रवेग a = 2 मीटर/सेकंद2
जेव्हा एखादी वस्तू विश्रांतीपासून सुरू होते, तेव्हा 1 सेकंद आणि 5 सेकंदात एकूण अंतर कापले जाते,
s = ut + 1/2 at 2
वस्तू विश्रांतीवर आहे, म्हणून, u = 0 m/s.
s 2 - s 1 = 24 मीटर
एकूण घेतलेला वेळ, t = t 2 - t 1 = 5 - 1 = 4 सेकंद
सरासरी वेग = एकूण विस्थापन/ एकूण वेळ कालावधी
सरासरी वेग = 24/4 = 6 मीटर/सेकंद
वेळ 1 s आणि 5 s दरम्यानचा सरासरी वेग = 6 मीटर/सेकंद
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