In the following question, four number pairs are given. In each pair the number on left side of (–) is related to the number of the right side of (–) with some Logic/Rule /Relation. Three pairs are similar on basis of same Logic/Rule/Relation. Select the odd one out from the given alternatives. (NOTE: Operations should be performed on the whole numbers, without breaking down the numbers into its constituent digits. E.g.13 – Operations on 13 such as adding /subtracting /multiplying etc. to 13 can be performed. Breaking down 13 into 1 and 3 and then performing mathematical operations on 1 and 3 is not allowed)

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SSC CHSL Tier-I Exam 2022 Official Paper (Held On: 16 March, 2023 Shift 3)
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  1. 28125 – 3125
  2. 11322 – 1258
  3. 49374 – 5483
  4. 49401 – 5489

Answer (Detailed Solution Below)

Option 3 : 49374 – 5483
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Detailed Solution

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The logic followed here is:

Logic: 1st number ÷ 9 = 2nd number.

Now, checking the options:

Option 1) 28125 – 3125 → 28125 ÷ 9 = 3125.

Option 2) 11322 – 1258 → 11322 ÷ 9 = 1258.

Option 3) 49374 – 5483 → 49374 ÷ 9 = 5486 ≠ 5483.

Option 4) 49401 – 5489 → 49401 ÷ 9 = 5489.

So, '49374 – 5483' odd among the given options.

Hence, the correct answer is "Option 3".

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