Question
Download Solution PDFIn the demand paging memory, a page table is held in registers. If it takes 1000 ms to service a page fault and if the memory access time is 10 ms, what is the effective access time for a page fault rate of 0.01?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFData:
Page fault rate = p = 0.01,
Page service time = S = 1000 ms
Memory access time = T = 10 ms
Concept:
Effective access time = (1 - p) × T + p × S
Calculation:
Effective access time = (1 - 0.01) × 10 + 0.01 × 1000
Effective access time = 0.99 × 10 + 10 = 9.9 + 10 = 19.9 ms
The effective access time is 19.9 msLast updated on Jul 2, 2025
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