Question
Download Solution PDFIn order to minimize both fifth and seventh harmonics, the coil span in three phase AC machines must be
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFFor eliminating nth harmonic coil span required is
\( = 180 \times \left( {\frac{{n - 1}}{n}} \right)\)
To eliminate 5th harmonic coil span required is
\(= 180 \times \left( {\frac{4}{5}} \right) = 144^\circ\)
To eliminate 7th harmonic coil span required is
\(= 180 \times \left( {\frac{6}{7}} \right) = 154.285^\circ\)
To eliminate both 5th and 7th harmonic, we should take average of both i.e.
\(= \frac{{144^\circ\; + \;154.28^\circ }}{2} = 149.14^\circ \approx 150^\circ\)
150° is \(\frac{5}{6}\) parts of 180° i.e. pole pitch
Hence, the coil span in three phase AC machines must be \(\frac{5}{6}th\) of pole pitch.Last updated on May 28, 2025
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