Question
Download Solution PDFIn a school, the number of students in class 4th, 5th and 6th were 188, 282 and 423 respectively. If each class is divided into sections and each section had the same number of students, then what was the minimum total number of sections in these three classes?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
The number of students in class 4th, 5th and 6th = 188, 282 and 423
Calculation:
HCF of 188, 282 and 423 is
⇒ 188 = 2 × 2 × 47
⇒ 282 = 2 × 3 × 47
⇒ 423 = 3 × 3 × 47
So, HCF = 47
Now,
Number of students in class 4th = (188/47) = 4
Number of students in class 5th = (282/47) = 6
Number of students in class 6th = (423/47) = 9
The minimum total number of sections in these three classes is
⇒ (4 + 6 + 9)
⇒ 19
∴ Minimum number of sections is 19
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