If x2 - 1, 2x and x+ 1 are the three sides of a right angled triangle, then which of the following can be its hypotenuse?

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  1. x2 + 1
  2. x2
  3. 2x
  4. x2 - 1

Answer (Detailed Solution Below)

Option 1 : x2 + 1
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Detailed Solution

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Given:

Three sides of the right-angled triangle: x2 - 1, 2x, x2 + 1

Formula used:

In a right-angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

Calculations:

Hypotenuse2 = Side12 + Side22

Let x2 + 1 be the hypotenuse.

⇒ (x2 + 1)2 = (x2 - 1)2 + (2x)2

⇒ (x2 + 1)2 = x4 - 2x2 + 1 + 4x2

⇒ x4 + 2x2 + 1 = x4 + 2x2 + 1 

⇒ Since LHS = RHS

⇒ So, Hypotenuse2 = Side12 + Side22

⇒ Hence, (x2 + 1) is the hypotenuse of the given triangle.

∴ The correct answer is x2 + 1

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