If uncertainty in the position of the electron is zero, then its uncertainty in momentum will be:

Concept:

Heisenberg’s Uncertainty Principle:

• It states that it is impossible to determine simultaneously, the exact position and exact momentum (or velocity) of an electron.
• Mathematically, it can be given as

\({\rm{\Delta }}x \times {\rm{\Delta }}{p_x} \ge \frac{h}{{4\pi }}\)

∆x is uncertainty in position, ∆p_x is uncertainty in momentum at position x.​

Explanation:

Now, it is given that uncertainty in  position is zero.

∆x = 0

But, by the uncertainty principle

\({\rm{\Delta }}x \times {\rm{\Delta }}{p_x} \ge \frac{h}{{4\pi }} \)

\(\implies {0} \times {\rm{\Delta }}{p_x} \ge \frac{h}{{4\pi }}\)

\(\implies {\rm{\Delta }}{p_x} \ge \frac{h}{{4\pi \times 0 }} \)

Now anything divided by zero is infinity. So, ∆px is infinity.

So, infinity is the correct answer.