If, in a series, there are m items whose ranks are common, then which factor is added for correction for each repeating value in both series?

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SSC CGL Tier-II ( JSO ) 2019 Official Paper ( Held On : 17 Nov 2020 )
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  1. \(\dfrac{1}{12}m\)
  2. \(\dfrac{1}{12}m(m-1)(m+1)\)
  3. \(\dfrac{1}{12}(m-1)(m+1)\)
  4. \(\dfrac{1}{12}m(m-1)\)

Answer (Detailed Solution Below)

Option 2 : \(\dfrac{1}{12}m(m-1)(m+1)\)
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Detailed Solution

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Explanation

According to  Spearman's rank correlation coefficient when ranks are repeated is as follows - 

⇒ rs = 1 - 6[(∑d2 + (m13 - m1)/12 + (m23 - m2)/12 + -------)]/n(n2 - 1)

m1, m2 ----- are the number of repetitions of the ranks

(m13 - m1)/12 ----- are corresponding factors

∴ The factor is added for each repeating value in the both series is given by (m3 - m)/12 = m(m2 - 1)/12 = m(m - 1)(m + 1)/12

Originally the spearsman rank correlation is denotted by rs = 1-6∑d2/n(n2 - 1)

 

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