If areas of similar triangles ΔABC and ΔDEF are x² cm² and y2 cm2 respectively, and EF = a cm, then BC (in cm) is:

Question

Question

This question was previously asked in

SSC CGL 2022 Tier-I Official Paper (Held On : 01 Dec 2022 Shift 2)

Answer 1

Given:

Areas of similar triangles ΔABC and ΔDEF are x2 cm2 and y2 cm2 respectively

EF = a cm

Concept used:

If two triangles are similar, then the ratio of the area of both triangles is proportional to the square of the ratio of their corresponding sides.

Calculation:

As ΔABC ∼ ΔDEF

So, (BC/EF)² = Area of ΔABC/Area of ΔDEF

⇒ BC²/a2 = x²/y²

⇒ BC/a = x/y

⇒ BC = ax/y

∴ BC (in cm) is \(\frac{a x}{y}\).

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