If 4 coins are tossed once then what is the probability of getting exactly 2 heads?

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OPSC ASO (Maths & Reasoning) 27 Aug 2022 Official Paper
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  1. 7/8
  2. 5/8
  3. 1/2
  4. 3/8

Answer (Detailed Solution Below)

Option 4 : 3/8
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Given:

Number of coins tossed = 4

Number of heads required = 2

Each coin has two outcomes: Head (H) or Tail (T).

Formula Used:

Probability of an event = (Number of favorable outcomes) / (Total number of outcomes)

Total outcomes for tossing n coins = 2n

Number of ways to get r heads in n tosses = nCr = n! / [r!(n - r)!]

Calculation:

Total number of outcomes = 24 = 16

Number of ways to get exactly 2 heads = 4C2 = 4! / [2!(4 - 2)!]

⇒ 4C2 = (4 × 3) / (2 × 1)

⇒ 4C2 = 6

Probability of getting exactly 2 heads = (Number of favorable outcomes) / (Total number of outcomes)

⇒ Probability = 6 / 16

⇒ Probability = 3 / 8

The probability of getting exactly 2 heads is 3/8.

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