Question
Download Solution PDFदो समान कारों A और B की गतिज ऊर्जाएँ क्रमशः 100 J और 225 J हैं। ब्रेक लगाने पर, कार A, 1000 m के बाद और कार B, 1500 m के बाद रुक जाती है। यदि कारों A और B पर ब्रेक द्वारा लगाए गए बल क्रमशः Fₐ और Fb हैं, तो अनुपात Fₐ/Fb है:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसही विकल्प: (2) 2/3 है।
कार्य-ऊर्जा प्रमेय से
कार्य = Δ गतिज ऊर्जा
⇒ F . S = Δ गतिज ऊर्जा
⇒ (Δगतिज ऊर्जा)A / (Δगतिज ऊर्जा)B = - FA SA / FB SB
⇒ (-100) / (225) = - FA(1000) / FB(1500)
FA / FB = 2 / 3
Last updated on Jun 16, 2025
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