Question
Download Solution PDFमाना \(\rm f(x) = 2x^2+ \dfrac{1}{x}\) है तो f'(1) क्या है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFअवधारणा:
उपयोग किया गया सूत्र:
यदि f(x) = xn हो तो f'(x) = n xn - 1
गणना:
दिया गया है:
\(\rm f(x) = 2x^2+ \dfrac{1}{x}\)
x के संबंध में अवकलन करने पर, हम प्राप्त करते है
⇒ f'(x) = 4x - \(\frac{1}{x^2}\)
x = 1 रखने पर
f'(x) = 4 × 1 - \(\frac{1}{1^2}\)
f'(-1) = 4 - 1 = 3
∴ f'(1) का मान 3 है
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