Question
Download Solution PDFएक वृत्त जिसका व्यास 44 cm है, उसकी एक जीवा की लम्बाई 22 cm है। जीवा की लघु चाप की लम्बाई क्या है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFधारणा:
लघु चाप की लंबाई = \(\frac{\theta }{{360}} \times 2\pi r\)
गणना:
दिया गया डेटा;
व्यास = 44 cm
\({\rm{Radius}} = {\rm{}}\frac{{{\rm{Diameter}}}}{2}{\rm{}} = {\rm{}}\frac{{44}}{2}{\rm{}} = {\rm{\;}}22{\rm{cm}}\)
जीवा की लंबाई = 22 cm
आकृति
त्रिभुज AOB में;
OA = OB = त्रिज्या = 22 cm
AB = 22 cm
∵ सभी भुजा समान हैं इसलिए त्रिभुज समबाहु है
∴ सभी कोण समान हैं, \(\theta = 60\)
\({\rm{Length\;of\;arc}} = {\rm{}}\frac{{\rm{\theta }}}{{360}} \times 2{\rm{\pi r}} = {\rm{}}\frac{{60}}{{360}} \times 2 \times \frac{{22}}{7} \times 22{\rm{}} = {\rm{}}\frac{1}{6} \times \frac{{968}}{7}{\rm{}} = {\rm{}}\frac{{484}}{{21}}{\rm{\;cm}}\)
Last updated on Jun 18, 2025
->UPSC has extended the UPSC NDA 2 Registration Date till 20th June 2025.
-> A total of 406 vacancies have been announced for NDA 2 Exam 2025.
->The NDA exam date 2025 has been announced. The written examination will be held on 14th September 2025.
-> The selection process for the NDA exam includes a Written Exam and SSB Interview.
-> Candidates who get successful selection under UPSC NDA will get a salary range between Rs. 15,600 to Rs. 39,100.
-> Candidates must go through the NDA previous year question paper. Attempting the NDA mock test is also essential.