Question
Download Solution PDFएक साफ शुष्क रेत नमूने को प्रत्यक्ष अपरूपण परीक्षण में जांचा जाता है। विफलता पर लम्बवत प्रतिबल और अपरूपण प्रतिबल दोनों 120 kN/m2 के बराबर हैं। रेत के अपरूपण प्रतिरोध का कोण कितना होगा ?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFमिट्टी के नमूने का अपरूपण प्रतिबल निम्न द्वारा दिया जाता है,
τ = c + σ tan ϕ
जहां , τ = मिट्टी का अपरूपण प्रतिबल
σ = मिट्टी का लम्बवत प्रतिबल
c = संसंजन
ϕ = आंतरिक घर्षण या अपरूपण प्रतिरोध का कोण
गणना:
शुष्क मिट्टी नमूना, So, C = 0
σ = τ = 120 kN / m2
τ = 0 + σ tan ϕ ⇒ 120 = 120 tan ϕ
⇒ tan ϕ = 1
⇒ ϕ = 45°
Last updated on Jul 2, 2025
-> BPSC AE 2025 exam date has been revised. The exam will be conducted on July 17, 18 & 19 now.
-> Candidates who were facing technical issues while filling form can now fill the BPSC AE application form 2025 without any issue.
->BPSC AE age limit 2025 has been revised. Also Check the BPSC AE Syllabus and Exam Pattern
->BPSC AE application form 2025 was released on April 30. The last date to fill BPSC AE form 2025 was May 28.
->BPSC AE interview call letters released for Advt. 32/2024.
->BPSC AE notification 2025 has been released.
->A total of 1024 vacancies are announced through BPSC AE recruitment 2025
->The BPSC Exam Calendar 2025 has been released for the Assistant Engineer Recruitment.
-> The selection will be based on a written exam and evaluation of work experience.
-> Candidates with a graduation in the concerned engineering stream are eligible for this post.
-> To prepare for the exam solve BPSC AE Previous Year Papers. Also, attempt the BPSC AE Civil Mock Tests.