Question
Download Solution PDFएक कार का प्रारंभिक वेग 12 m/s है और इसे 45 m के दूरी पर विरामावस्था में लाया जाता है। कार का त्वरण है
Answer (Detailed Solution Below)
Detailed Solution
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दिया गया है:
प्रारंभिक वेग, u = 12 मी/से
अंतिम वेग, v = 0 मी/से (चूँकि कार रुक जाती है)
दूरी, s = 45 मी
सूत्र का उपयोग करते हुए:
v2 = u2 + 2as
⇒ (0)2 = (12)2 + 2 x a x 45
⇒ 0 = 144 + 90a
⇒ 90a = -144
⇒ a = -1.6 मी/से2
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