Question
Download Solution PDFFind the current through the 20 Ω resistor:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept
According to KCL, the algebraic sum of incoming and outgoing currents at a node are equal.
At node O:
\(I_1+I_2=I_3+I_4+I_5\)
Calculation
Assuming the voltage (V) at node A:
\({V-10\over 2}+{V\over 20}+{V+20\over 4}=0\)
\({10V-100+V+5V+100\over 20}=0\) ⇒V = 0
The current across the 20 Ω resistor \(I={0\over 20}\) ⇒I = 0 A
Last updated on Jul 1, 2025
-> SSC JE Electrical 2025 Notification is released on June 30 for the post of Junior Engineer Electrical, Civil & Mechanical.
-> There are a total 1340 No of vacancies have been announced. Categtory wise vacancy distribution will be announced later.
-> Applicants can fill out the SSC JE application form 2025 for Electrical Engineering from June 30 to July 21.
-> SSC JE EE 2025 paper 1 exam will be conducted from October 27 to 31.
-> Candidates with a degree/diploma in engineering are eligible for this post.
-> The selection process includes Paper I and Paper II online exams, followed by document verification.
-> Prepare for the exam using SSC JE EE Previous Year Papers.