Determine the voltages at the node 'a' and node 'b' in the given network.

This question was previously asked in
HPCL Engineer Electrical 01 Nov 2022 Official Paper
View all HPCL Engineer Papers >
  1. Va = 3 V, Vb = 3 V
  2. Va = 11 V, V= 3 V
  3. V= 11 V, Vb = 11 V
  4. Va = 3 V, Vb = 11 V

Answer (Detailed Solution Below)

Option 4 : Va = 3 V, Vb = 11 V
Free
Soil Mechanic for All AE/JE Civil Exams Mock Test
20 Qs. 20 Marks 20 Mins

Detailed Solution

Download Solution PDF

Kirchhoff’s Current Law (KCL):

This law is also known as the junction rule or current law (KCL). According to it the algebraic sum of currents meeting at a junction is zero i.e. Σ i = 0.


Calculation:

The given circuit is 

There are two nodes a and b

The current flow through the 2 Ω Resistor  is the sum of the  current source Iba = 4 A

At node b

 = 1+ 3

Vb - V= 8 ------(1)

At node a

 -+ 3 = 0 ------(2)

By substituting 1 in 2

we get

Va = 3 V, Vb = 11 V

Latest HPCL Engineer Updates

Last updated on Jun 2, 2025

-> HPCL Engineer 2025 notification has been released on June 1, 2025.

-> A total of 175 vacancies have been announced for the HPCL Engineer post in Civil, Electrical, Mechanical, Chemical engineering.

-> HPCL Engineer Online application will be activated from 1st June 2025 to 30th June 2025.

-> Candidates with a full-time engineering discipline in the relevant stream are eligible to apply.

-> The selection will be based on a Computer Based Test Group Task and/or Interview. Prepare for the exam using HPCL Engineer Previous Year Papers.

Hot Links: lotus teen patti all teen patti teen patti casino apk teen patti lotus