Calculate the limiting value of molar conductance when degree of ionisation is 2.02 and molar conductance is 4.04 Sm2 mole? at 25°C. 

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DSSSB PGT Chemistry (Female) Official Paper (Held On: 06 Jul, 2018 Shift 1)
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  1. 2 Sm-2 mole-1
  2. Sm2 mole-1
  3. \(\frac{1}{2}\) Sm2 mole-1
  4. \(\frac{1}{2}\) Sm-2 mole-1

Answer (Detailed Solution Below)

Option 2 : 2 Sm2 mole-1
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Detailed Solution

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CONCEPT:

Limiting Molar Conductance (Λmo)

  • The limiting molar conductance (Λmo) represents the molar conductivity when ionization is complete, i.e., at infinite dilution.
  • The relationship between molar conductance (Λm) and limiting molar conductance (Λmo) is given by:

    Λm = (Λmo) × degree of ionization

EXPLANATION:

  • From the given data:
    • Molar conductance (Λm) = 4.04 Sm2 mol-1
    • Degree of ionization = 2.02
  • Using the formula:
    • Λmo = Λm / degree of ionization
    • = 4.04 Sm2 mol-1 / 2.02
    • = 2 Sm2 mol-1

Therefore, the limiting molar conductance (Λmo) is 2 Sm2 mol-1.

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