Question
Download Solution PDFCalculate the hook length of the bar in one side with a diameter of 16 mm.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
- The length of one hook may be taken as 9× dia and the total length is taken as L + 18 D, as shown in figure.
So, the length of hook = 9 × 16 = 144 mm
Additional Information
- For 45 degree cranked or bent up bar
- The additional length for one bent up is = difference in length of hypotenuse and base = = d/sin45°- d = = 0.42d = 0.45d ( approx)
- For 30 degree cranked or bent up bar
- Inclined length of crank = d/sin30° = 2d
- The horizontal length of crank = d/tan30 = 1.73d
- The extra length required for one crank = 2d-1.73d = 0.27d = 0.3d (say)
- For a bar cranked at both ends at 30 the additional length is equal to 2 × 0.3d = 0.6d
Last updated on Jul 1, 2025
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