Question
Download Solution PDFএকই শীর্ষবিন্দু ভাগ করা একটি আয়তঘনকের তিনটি তলের পৃষ্ঠের ক্ষেত্রফল হল 20 মি2 , 32 মি2 এবং 40 মি2 হলে, আয়তঘনকের আয়তন কত?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFপ্রদত্ত:
L × B = 20 বর্গমিটার
B × H = 32 বর্গমিটার
L × H = 40 বর্গমিটার
যেখানে L = দৈর্ঘ্য, B = প্রস্থ, H = উচ্চতা
প্রযুক্ত সূত্র:
আয়তঘনকের সমগ্র তলের ক্ষেত্রফল = L × B + B × H + L × H
আয়তঘনকের আয়তন = LBH
সমাধান:
প্রশ্নানুসারে,
⇒ L × B × B × H × L × H = 20 × 32 × 40
⇒ L2B2H2 = 25600
⇒ LBH = 160
∴ আয়তঘনকের আয়তন হল 160 মি3
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