Question
Download Solution PDFBandwidth of a parallel resonance circuit is equal to 26.52 Hz and quality factor of the circuit is given by 1.7322. What is the value of resonant frequency?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFThe correct answer is option 3):(45.94 Hz)
Concept:
The quality factor is defined as the ratio of the maximum energy stored to maximum energy dissipated in a cycle
\(Q = R\times\sqrt{\frac{C}{L}}\)
bandwidth = \(f_r \over Q\)
fr = \(\frac{1}{{2\pi \sqrt {LC} }} \)
where
fr is the resonant frequency
Q is the quality factor
R is the resistance
L is the inductance
C is the capacitance
Calculation:
bandwidth = 26.52 Hz
Q = 1.7322.
fr = bandwidth × Q
= 45.94 Hz
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