‘b’ is 25% more than ‘a’ and ‘c’ is 100% more than ‘b’. If the value of 'a' is 4/5, then what is the value of 'c'?

Question

Question

This question was previously asked in

PGCIL DT Civil 13 Aug 2021 Official Paper (NR I)

Answer 1

Given:

‘b’ is 25% more than ‘a’ and ‘c’ is 100% more than ‘b’.

The value of a = \(\frac{4}{{5}}\)

Calculation:

The value of a = \(\frac{4}{{5}}\)

According to the question

‘b’ is 25% more than ‘a’

⇒ b = (\(\frac{4}{{5}}\) + \(\frac{25}{{100}}\) × \(\frac{4}{{5}}\))

⇒ b = (\(\frac{4}{{5}}\) + \(\frac{1}{{5}}\))

⇒ b = \(\frac{5}{{5}}\) = 1

Now, ‘c’ is 100% more than ‘b’

⇒ c = (1 + \(\frac{100}{{100}}\) × 1)

⇒ c = ( 1 + 1)

⇒ c = 2

∴ The required value of c is 2.

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