Question
Download Solution PDFAssuming constant transmission efficiency, if voltage is increased ‘n’ times, the size of the conductor would be
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFIf we want to transmit the same number of watts, the current will be \(\frac{1}{n}\) when the voltage is increased by n.
For the same amount of loss, the new diameter of the wire will be 1/n.
The amount of copper will be \(~\frac{1}{{{n}^{2}}}\)
So, when voltage is increased by n times then for same efficiency size of conductor is reduced to \(\frac{1}{{{n}^{2}}}~\) that of the original.Last updated on Jun 16, 2025
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